Name the smallest angle of abc

What is the coefficient of y int the expression 2x4+3y

lapo4ka [179]

The coefficient of y = 3

coefficient = the constant in front of a variable
Constant means that the number will not change.

hope this helps

6 0

3 years ago

Suppose the value R(d) of d dollars in euros is given by R(d)-d The cost P(n) in dollars to purchase and ship n purses is given

S_A_V [24]

Corrected Question

Suppose the value R(d) of d dollars in euros is given by $R(d)=\dfrac67 d$ . The cost in dollars to purchase and ship n purses is given by P(n)=66n+23. Write a formula for the cost, Q(n) in euros to purchase and ship n purses.

Answer:

$Q(n)=\dfrac67(66n+23)$

Step-by-step explanation:

The value R(d) of d dollars in euros is given by $R(d)=\dfrac67 d$

Therefore:

$R(1)=\dfrac67$

$T$hat is, 1 dollars =\dfrac67$ euros$

The cost P(n) in dollars to purchase and ship n purses is given by:

$P(n) = 66n+23.$

Therefore, the cost, Q(n) in euros to purchase and ship n purses

$=\dfrac67 \cdot P(n)\\Q(n)=\dfrac67(66n+23)$

8 0

3 years ago

HELPPPP NOWW

Effectus [21]

Answer:

Volume of a parallelogram is v=whl

Area of s parallelogram is A= bh

Circumference of a circle= rd

Area of a circle= rd^2

Area of a triangle is 1/a bh

Area of a trapezoid is 1/2(b1 + b2)h

Perimeter of a quadrilateral is 2L + 2W

I couldn't drag the image but I knew what I was doing!

8 0

3 years ago

Solve by setting up a system of linear equations with 2 variables and 2 unknowns. Two hundred seventy six students enrolled in a

jeyben [28]

Let us say ,

x=number of students who passed

y=number of students who failed

total number of students =276

x+y=276..................(1)

We are given 5 times the number of students passed as failed.

x=5y.............(2)

plugging value of x from (2) in (1),

5y+y=276

6y=276

y=46

x=5y=46*5=230

x=number of students who passed=230

4 0

3 years ago

In 2002, the mean age of an inmate on death row was 40.7 years with a standard deviation of 9.6 years according to the U.S. Depa

marissa [1.9K]

Answer:

The 95% confidence interval for the current mean age of death-row inmates is between 42.23 years and 35.57 years.

Step-by-step explanation:

The confidence interval of the mean is given by the next formula:

$\\ \overline{x} \pm z_{1-\frac{\alpha}{2}}\frac{\sigma}{\sqrt{n}}$ [1]

We already know (according to the U.S. Department of Justice):

The (population) standard deviation for this case (mean age of an inmate on death row) has a standard deviation of 9.6 years ( $\\ \sigma = 9.6$ years).
The number of observations for the sample taken is $\\ n = 32$ .
The sample mean, $\\ \overline{x} = 38.9$ years.

For $\\ z_{1-\frac{\alpha}{2}}$ , we have that $\\ \alpha = 0.05$ . That is, the level of significance $\\ \alpha$ is 1 - 0.95 = 0.05. In this case, then, we have that the z-score corresponding to this case is:

$\\ z_{1-\frac{\alpha}{2}} = z_{1-\frac{0.05}{2}} = z_{1-0.025} = z_{0.975}$

Consulting a cumulative standard normal table, available on the Internet or in Statistics books, to find the z-score associated to the probability of, $\\ P(z$ , we have that $\\ z = 1.96$ .

Notice that we supposed that the sample is from a population that follows a normal distribution. However, we also have a value for n > 30, and we already know that for this result the sampling distribution for the sample means follows, approximately, a normal distribution with mean, $\\ \mu$ , and standard deviation, $\\ \sigma_{\overline{x}} = \frac{\sigma}{\sqrt{n}}$ .

Having all this information, we can proceed to answer the question.

Constructing the 95% confidence interval for the current mean age of death-row inmates

To construct the 95% confidence interval, we already know that this interval is given by [1]:

$\\ \overline{x} \pm z_{1-\frac{\alpha}{2}}\frac{\sigma}{\sqrt{n}}$

That is, we have:

$\\ \overline{x} = 38.9$ years.

$\\ z_{1-\frac{\alpha}{2}} = 1.96$

$\\ \sigma = 9.6$ years.

$\\ n = 32$

Then

$\\ 38.9 \pm 1.96*\frac{9.6}{\sqrt{32}}$

$\\ 38.9 \pm 1.96*\frac{9.6}{5.656854}$

$\\ 38.9 \pm 1.96*1.697056$

$\\ 38.9 \pm 3.326229$

Therefore, the Upper and Lower limits of the interval are:

Upper limit:

$\\ 38.9 + 3.326229$

$\\ 42.226229 \approx 42.23$ years.

Lower limit:

$\\ 38.9 - 3.326229$

$\\ 35.573771 \approx 35.57$ years.

In sum, the 95% confidence interval for the current mean age of death-row inmates is between 42.23 years and 35.57 years.

Notice that the "mean age of an inmate on death row was 40.7 years in 2002", and this value is between the limits of the 95% confidence interval obtained. So, according to the random sample under study, it seems that this mean age has not changed.

7 0

3 years ago