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valkas [14]
2 years ago
10

Please help me solve this

Chemistry
1 answer:
Anettt [7]2 years ago
4 0

Answer:

phele to padte nahi phir help magte h

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Describe the separation technique that could be used to separate two colorless liquids with varying boiling points.
Over [174]
Distillation; either simple or fractional macroscale depending on how far apart the boiling points are. 
3 0
3 years ago
Suppose you start with one liter of vinegar and repeatedly remove 0.08 L, replace with water, mix, and repeat. a. Find a formula
Bumek [7]

Answer:

0.92^n

Explanation:

Given that :

Initial amount of vinegar = 1 Litre

Number of litres removed repeatedly = 0.08 Litre

Since the amount removed each time is constant, then ;

Initial % = 100% = 100/100 = 1

. Using the relation :

Amount of vinegar in mixture :

Initial * (1 - amount removed / initial amount)^n

n = number of times repeated

1 * (1 - 0.08/1)^n

1 * (1 - 0.08)^n

1 * 0.92^n

Hence,

For nth removal,

Concentration will be :

0.92^n ; for n ≥ 1

7 0
2 years ago
List out causes of deforestation​
Vsevolod [243]
Agriculture
Unsustainable forest management
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Paper
7 0
2 years ago
Read 2 more answers
I have these answered, but I'd like someone to check them for me? Plz and thanks :)
zlopas [31]
1. The third option is the least soluble in water because it is the chain with the most number of hydrocarbons. Next is the second option while the first one is the most soluble.
2. Statements 1 and 2 are true. The third option is not true all the time because it depends on the structure of the compound.
4 0
4 years ago
How many joules are needed to change the temperate of 22g of water from 18°C to 33°C?
Ira Lisetskai [31]

Answer:

Q =  1379.4 J

Explanation:

Given data:

Mass of water = 22  g

Initial temperature = 18°C

Final temperature = 33°C

Heat absorbed = ?

Solution:

Specific heat capacity:

It is the amount of heat required to raise the temperature of one gram of substance by one degree.

Specific heat capacity of water is 4.18 J/g. °C

Formula:

Q = m.c. ΔT

Q = amount of heat absorbed or released

m = mass of given substance

c = specific heat capacity of substance

ΔT = change in temperature

ΔT = 33°C - 18 °C

ΔT =  15°C

Q = 522 g ×4.18 J/g.°C× 15°C

Q =  1379.4 J

5 0
3 years ago
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