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xeze [42]
3 years ago
6

The empirical formula for compound is P2O5. The molar mass of the compound is 283.89g. What is the molecular formula?

Chemistry
1 answer:
Furkat [3]3 years ago
8 0

Answer:

P4O10

Explanation:

(P2O5)n=283.89

62+80=283.89

142n=283.89

n=2

P2O10

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A solution is made by mixing equal masses of methanol, CH4O, and ethanol, C2H6O. Determine the mole fraction of each component t
Serggg [28]

Answer: mole fraction of methanol = 0.590

mole fraction of ethanol = 0.410

Explanation:

We are given:

Equal masses of methanol CH_4O and ethanol C_2H_6O are mixed.

let the mass be x g.

Calculating the moles of methanol in the solution, by using the equation:

\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}=\frac{xg}{32.04g/mol}

Calculating the moles of ethanol in the solution, by using the equation:

\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}=\frac{xg}{46.07g/mol}

To calculate the mole fraction of methanol, we use the equation:

\chi_{methanol}=\frac{n_{methanol}}{n_{methaol}+n_{ethanol}}

\chi_{methanol}=\frac{\frac{xg}{32.04g/mol}}{\frac{xg}{32.04g/mol}+\frac{xg}{46.07g/mol}}=0.590

To calculate the mole fraction of ethanol, we use the equation:

\chi_{ethanol}=\frac{n_{ethanol}}{n_{methaol}+n_{ethanol}}

\chi_{ethanol}=\frac{\frac{xg}{46.07g/mol}}{\frac{xg}{32.04g/mol}+\frac{xg}{46.07g/mol}}=0.410

Thus mole fraction of methanol is 0.590 and mole fraction of ethanol 0.410 in three significant figures.

5 0
3 years ago
Which functional group does the molecule below have?
Andrei [34K]

Answer:

Hydroxyl

Explanation:

A hydroxyl group is a functional group that attaches to some molecules containing an oxygen and hydrogen atom, bonded together. Also spelled hydroxy, this functional group provides important functions to both alcohols and carboxylic acids.

3 0
3 years ago
The rate at which a chemical reaction occurs cannot be changed. (True or False)
frozen [14]
The answer is false.
8 0
3 years ago
Copper is commonly mined as an ore with a variable percent composition of copper (II) sulfide. This ore is also sometimes referr
pantera1 [17]

Answer:

m_{CuO}=93.6gCuO

Explanation:

Hello,

In this case, the undergoing chemical reaction is:

CuS+\frac{3}{2} O_2\rightarrow CuO+SO_2

Thus, given the 1.00-kg of 12.5% ore, we can compute the theoretical yield of copper (II) oxide via stoichiometry:

m_{CuO}^{theoretical}=1.00kgCuS*\frac{1000gCuS}{1kgCuS} *\frac{12.5gCuS}{100gCuS} *\frac{1molCuS}{95.6gCuS} *\frac{1molCuO}{1molCuS} *\frac{79.5gCuO}{1molCuO} \\\\m_{CuO}^{theoretical}=103.95gCuO

Whereas the third factor accounts for the percent purity of the covellite. Then, given the percent yield, we can compute the actual yield by:

m_{CuO}=103.95gCuO*0.9\\\\m_{CuO}=93.6gCuO

Regards.

6 0
3 years ago
During the early paleozoic land plants begin to grow which consisted of
Gnesinka [82]
B. (Hope This Helps)
7 0
3 years ago
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