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Butoxors [25]
3 years ago
7

2. Find the value of the expression 21 – 2a if a = 3.

Mathematics
2 answers:
timama [110]3 years ago
7 0

Answer:

A

Step-by-step explanation:

we just substitute the value of "a" given in the above expression we get

21-2(3)

21-6=15

poizon [28]3 years ago
6 0

<u>Answer:</u>

<em><u>a. 15</u></em>

<u />

<u>Explanation:</u>

<u />

Step 1 - Input the value of 'a' in the expression.

21 - 2a

21 - 2(3)

Step 2 - Multiply two and three

21 - 2(3)

21 - 6

Step 3 - Subtract six from twenty one

21 - 6

15

Therefore, the value of the expression 21 - 2a if a = 3 is <u><em>a. 15.</em></u>

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MakcuM [25]

Answer:

a) 0.1509

b) 0.8314

Step-by-step explanation:

Since there are only two options for each question, the probability that he guesses right is p = 0.50, and the probability that he guesses wrong is q = 0.50

There is a total of 15 questions in the test so we can use the formula for a binomial distribution with parameters n = 15, p = 0.5, q = 0.5

a)  If he needs to score 10 or more correct to pass, what is the probability that he will fail the exam?

To find this probability we will need to find the probability:

P ( X < 10) or

(1 -  P (x ≥10))

Remember that the formula for a binomial distribution is:

P(x) = \left[\begin{array}{ccc}n\\x\end{array}\right] p^{x} q^{n-x}

We can solve this by using the parameters given before and make x = 10, 11, 12, 13, 14, 15 and use the formula:

P(he fails the exam) = 1 - P (x≥10)

= 1 - (P(x=10) + P(x=11) + P(x=12) + P(x=13) + P(x=14) + P(x=15))

= 0.1509

b) Find the probability that he answers 6 to 11 inclusive)

We're going to use the same formula but we will do:

P (x = 6) + P (x = 7) + P (x = 8) + P (x = 9) + P (x = 10) + P (x = 11)

=0.1527 + .1964 + .1964 + 0.1527 + 0.0916 + 0.0416

= 0.8314

Therefore the probability that he answers 6 to 11 inclusive is 0.8314

4 0
3 years ago
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