Answer:
Part A) The surface area of prism B is equal to the surface area of prism A multiplied by the scale factor (m) squared
Part B) The Volume of prism B is equal to the Volume of prism A multiplied by the scale factor (m) elevated to the cube
Step-by-step explanation:
Part A) we know that
The scale factor is equal to m
The surface area of the prism is equal to

where
B is the area of the base
P is the perimeter of the base
h is the height of the prism
we have
Prism A



substitute
![SA=[2(xy)+2(x+y)z]\ units^{2}](https://tex.z-dn.net/?f=SA%3D%5B2%28xy%29%2B2%28x%2By%29z%5D%5C%20units%5E%7B2%7D)
Prism B



substitute
![SB=[2(xym^{2})+2m(x+y)mz]\ units^{2}](https://tex.z-dn.net/?f=SB%3D%5B2%28xym%5E%7B2%7D%29%2B2m%28x%2By%29mz%5D%5C%20units%5E%7B2%7D)
![SB=[2(xym^{2})+2m^{2}(x+y)z]\ units^{2}](https://tex.z-dn.net/?f=SB%3D%5B2%28xym%5E%7B2%7D%29%2B2m%5E%7B2%7D%28x%2By%29z%5D%5C%20units%5E%7B2%7D)
therefore
The surface area of prism B is equal to the surface area of prism A multiplied by the scale factor (m) squared
Part B) we know that
The volume of the prism is equal to

where
B is the area of the base
h is the height of the prism
we have
Prism A


substitute
![VA=[(xyz]\ units^{3}](https://tex.z-dn.net/?f=VA%3D%5B%28xyz%5D%5C%20units%5E%7B3%7D)
Prism B


substitute
![VB=[(xym^{2})mz]\ units^{3}](https://tex.z-dn.net/?f=VB%3D%5B%28xym%5E%7B2%7D%29mz%5D%5C%20units%5E%7B3%7D)
![VB=[(xyzm^{3})]\ units^{3}](https://tex.z-dn.net/?f=VB%3D%5B%28xyzm%5E%7B3%7D%29%5D%5C%20units%5E%7B3%7D)
therefore
The Volume of prism B is equal to the Volume of prism A multiplied by the scale factor (m) elevated to the cube
as the line has the ends which has closed dot to indicate that the endpoint is part of the solution. Also its between the points -3 and 3.
Answer:
0.002
Step-by-step explanation:
Answer:
Step-by-step explanation:
The last three are irrational but I'm not sure about the first four.
Answer:
71
Step-by-step explanation:
Area of fig 1 = 1 x b = 7 x 4 = 28
Area of fig 2 = l x b = (7-2) x 3 = 5 x 3 = 15
Area of fig 1 = 1 x b = 7 x 4 = 28 (same as ig 1)
Area of whole fig = fig 1 + fig 2 + fig 3 = 28+15+28 = 71
I hope im right !!