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musickatia [10]
3 years ago
8

Rectangles J and K are similar. If the area of rectangle J is 440, what is the area of rectangle K? I need this today

Mathematics
1 answer:
Hunter-Best [27]3 years ago
4 0

Answer:

Area = 27.5

Step-by-step explanation:

Given

J_{Area} = 440

J_{Width} = 22

K_{Width} = 5.5

<em>See attachment</em>

Required

Determine the area of K

First, we need to calculate the length of the rectangle  J

J_{Length} * J_{Width} = J_{Area}

This gives:

J_{Length} * 22 = 440

Divide both sides by 22

\frac{J_{Length} * 22}{22} = \frac{440}{22}

J_{Length} = 20

So, the length of the rectangle J is 20.

Since both shapes are similar, then:

J_{Length} : J_{Width} = K_{Length} : `K_{Width}

Substitute the known values:

20 : 22 = K_{Length} : `5.5

Express as fraction:

\frac{20 }{ 22 }= \frac{K_{Length} }{ `5.5}

Make Length, the subject of formula

K_{Length} = \frac{5.5 * 20}{22}

K_{Length} = \frac{110}{22}

K_{Length} = 5

The area of K is:

Area = K_{Length} * K_{Width

Area = 5.5 * 5

Area = 27.5

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