The time required by the car to stop is 4.916 sec.
Since the car is moving with the constant deceleration we can apply the first equation of motion to calculate the time required by the car to stop.
The first equation of motion is given as
V=u+at
Here, V=final speed of the car=0 mi/h as the car stops
u =initial speed of the car=55 mi/hr=24.58 m/s
a= acceleartion =-5 m/s^2 (here negative sign indicates for deceleration)
Now applying the values in the first equation
V=u+at
0=24.58-5*t
t=4.916 sec
Therefore the car will stops in 4.916 sec.
5
If you go over 2 on the time bar, and you look for the black dot above the 2 on the bottom time bar, it would go up to 5.
Mr. Hitch taught us about sedimentary, metamorphic, and igneous rocks. He described how they were formed, what they contain, and showed us samples of each. He is a good geologist.
The missing word and answer is: geologist.
Answer:
Velocity will be equal to 7.31 m/sec
Explanation:
We have given mass of the student m = 61 kg
Height of the water slide h = 12.3 m
Acceleration due to gravity 
Potential energy is equal to 
Work done due to friction = -5800 J
So energy remained = 7352.94-5800 = 1552.94 J
This energy will be equal to kinetic energy
So 


v = 7.13 m/sec