Answer:
If the rifle is held loosely away from the shoulder, the recoil velocity will be of -8.5 m/s, and the kinetic energy the rifle gains will be 81.28 J.
Explanation:
By momentum conservation, <em>and given the bullit and the recoil are in a straight line</em>, the momentum analysis will be <em>unidimentional</em>. As the initial momentum is equal to zero (the masses are at rest), we have that the final momentum equals zero, so

now we clear
and use the given data to get that

<em>But we have to keep in mind that the bullit accelerate from rest to a speed of 425 m/s</em>, then <u>if the rifle were against the shoulder, the recoil velocity would be a fraction of the result obtained</u>, but, as the gun is a few centimeters away from the shoulder, it is assumed that the bullit get to its final velocity, so the kick of the gun, gets to its final velocity
too.
Finally, using
we calculate the kinetic energy as

The addition of vectors and the uniform motion allows to find the answers for the questions about distance and time are:
- The distance to go between airports A and C is 373.6 10³ m
- The time to go from airport A to B is 2117 s
Vectors are quantities that have modulus and direction, so their addition must be done using vector algebra.
In this case the plane flies towards the North a distance of y = 360 10³ m at an average speed of v = 170 m / s, when arriving at airport B it turns towards the East and travels from x = 100 10³ m, until' it the distance reaches the airport C
Let's use the Pythagoras theorem to find the distance traveled
R = Ra x² + y²
R = 10³
R = 373.6 10³ m
They indicate the average speed for which we can use the uniform motion ratio
v = 
t = 
They ask for the time in in from airport A to B, we calculate
t = 360 10 ^ 3/170
t = 2.117 10³ s
In conclusion we use the addition of vectors the uniform motion we can find the answer for the question of distance and time are:
- The distance to go between airports A and C B is 373.6 10³ m
- The time to go from airport A to B is 2117 s
Learn more here: brainly.com/question/15074838
Titan is the largest moon in Saturn.
Answer:
weight
Explanation:
the weight of an object on an airline is one of the most important thing a pilot has to consider when prepping a flight and that is because if there is too much weight then the plane simply can't fly. imagine if everyone wanted to bring a 50 kg box. there are at least 200 people. that alone is 10,000 lg of weight than you have to factor in all the people, wires on the plane, and certain appliances that some planes have.
Answer:
140m
70sec I cant show my work but I gave you a push
Explanation:
Brainliest?