Answer:
y = -8x+2020
Step-by-step explanation:
8x + y = 2020
Subtract 8x from each side
8x-8x + y = -8x+ 2020
y = -8x+2020
1. 5^2 = 25
2. 2^6 = 64
3. 25^(1/2) =5
Sin Q = oppo. / hypo
sin Q = 9/15
sin Q = 0.6
When the difference between one and two numbers is two, the two numbers are -10 and -12.
Given that,
The difference between one and two numbers is two. Twelve more than six times the second is four times the first.
We have to find the number.
We know that,
The system of equation we get
x=y-2 ----->equation(1)
4x=12+6y ----->equation(2)
Substitute for x in the equation(2)
4(y-2)=12+6y
4y-8=12+6y
4y-6y=12+8
-2y=20
y=-10
Substitute y=-10 in equation(1)
x=-10-2
x=-12
Therefore, The two numbers area -10 and -12 when the difference between one and two numbers is two.
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Answer:
is this a question
Step-by-step explanation: