by the use of elimination method
make all coefficients of subject to be eliminated similar..by multiplying the coefficients with one another
for eqn(i)
5(-10y+9x=-9)
-50y+45x=-45
for eqn(ii)
9(10y+5x=-5)
90y+45x=-45
-50y+45x=-45
90y+45x=-45
...subtract each set from the other...
we get
-140y+0=0
y=0
from eqn(i)
10y+5x=-5
0+5x=-5
x= -1
Answer:
distance from Houston to Galveston in kilometers will be: 80km
Step-by-step explanation:
Given
The distance from Houston to Galveston is about 50 miles.
i.e.
Kilometers in 1 Mile = 1.6 km
As the distance from Houston to Galveston is about 50 miles, so
The distance from Houston to Galveston in kilometers will be:
50(1.6) = 80 ∵ Kilometers in 1 Mile = 1.6 km
Therefore,
The distance from Houston to Galveston in kilometers will be: 80km
I don’t see the it the picture
Answer:
<h2>(3 + i)(4 + 2i) = 10 + 10i</h2>
Step-by-step explanation:
Use FOIL: (a + b)(c + d) = ac + ad + bc + bd
and i² = -1
