Answer: The correct answer is 11 yards of wallpaper border.
Step-by-step explanation: What Wendy needs to do is to calculate the perimeter of her bedroom. The perimeter of any given figure is simply a calculation of the entire measurement all around the given figure. In other words, the perimeter of Wendy's room denotes the addition of all the four side lengths of her bedroom.
The room has two sides both measuring 10 feet 5 inches. This gives a total of 20 feet 10 inches. It also has the other two sides both measuring 6 feet 1 inch and that too gives a total of 12 feet 2 inches. Adding them all together results in 32 feet 12 inches. Better still, the perimeter of the room is derived as;
Perimeter = 2 (L + W)
Perimeter = 2 (10'5" + 6'1")
Perimeter = 2(16'6")
Perimeter = 32'12"
Having in mind our conversion rate of 12 inches equals 1 foot, the results can be properly expressed as 32 feet plus 1 foot which gives us 33 feet.
If the perimeter of Wendy's room is now given as 33 feet, the conversion rate between feet and yards can now be applied. Having been given that
3 feet = 1 yard
Then 1 yard = 3 feet/3, that is
y = 3/3
Hence,
y = 33/3
y = 11
The results show that Wendy would needs to buy a total of 11 yards of wallpaper border.
Answer:
D) 72
Step-by-step explanation:
The way to find the area of this figure easily is to break it down in regular shapes we know. You can then see it as two horizontal rectangles on top and bottom, measuring 6 x 4 each, then a vertical rectangle in the middle measuring 4 x 6.
So, overall, we have 3 similar rectangles measuring 4x6 or 6x4... which are equivalent.
The area of each of those 3 rectangles is 24 units (6x4).
Since we have 3 of those: 3 * 24 = 72.
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<span>With 1026 being the mean score on the SAT and StDev of 209, Jessica has a score of 799/209 z-scores above the mean. Her z-score would be 3.823. The mean of the ACT and StDev are 20.8 and 4.8, respectively. A 28 ACT score would be 7.2/4.8 z-scores above the mean, for a z = 1.500. This means that Jessica has the higher z-score.</span>
