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77julia77 [94]
3 years ago
13

Can someone pls summarise this for me cbb ILL BRAINLIST U!!:)

Chemistry
1 answer:
Novosadov [1.4K]3 years ago
7 0
Electrons in an atom are found on different electron shells depending on how much energy they possess, and they determine how atoms will interact with each other. The outermost electron shell holds the valance electrons.
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Which of this is not an effect of humans using a natural recourse?
katen-ka-za [31]

Answer:

it can allow more room for additional living things in the habitat

Explanation:

Use water for an example.

- Taking water can destroy a fish habitat.

- Using excess water can cause water to run out.

- Taking/using water leaves less amounts for others/organisms.

Taking water does not allow additional room for organisms in a habitat.

5 0
3 years ago
Which of the following is a property of a metal?
BaLLatris [955]
The correct answer is the 3rd option Ductility is a property of a metal. It is the ability of a material to deform under tensile stress.It is characterized by the ability to be stretched into wire-like form which is an ability of metals.
8 0
3 years ago
Unlike the cell wall, the cell membrane is…
irakobra [83]
B: produces energy for the cell
5 0
4 years ago
Which phase change is exothermic?
DerKrebs [107]
Freezing, condensation, Deposition.
8 0
3 years ago
A 32.2 g iron rod, initially at 21.9 C, is submerged into an unknown mass of water at 63.5 C. in an insulated container. The fin
lorasvet [3.4K]

Answer : The mass of the water in two significant figures is, 3.0\times 10^1g

Explanation :

In this case the heat given by the hot body is equal to the heat taken by the cold body.

q_1=-q_2

m_1\times c_1\times (T_f-T_1)=-m_2\times c_2\times (T_f-T_2)

where,

c_1 = specific heat of iron metal = 0.45J/g^oC

c_2 = specific heat of water = 4.18J/g^oC

m_1 = mass of iron metal = 32.3 g

m_2 = mass of water = ?

T_f = final temperature of mixture = 59.2^oC

T_1 = initial temperature of iron metal = 21.9^oC

T_2 = initial temperature of water = 63.5^oC

Now put all the given values in the above formula, we get

32.3g\times 0.45J/g^oC\times (59.2-21.9)^oC=-m_2\times 4.18J/g^oC\times (59.2-63.5)^oC

m_2=30.16g\approx 3.0\times 10^1g

Therefore, the mass of the water in two significant figures is, 3.0\times 10^1g

3 0
3 years ago
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