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bonufazy [111]
3 years ago
11

Fill in the blank spot.

Chemistry
1 answer:
Anastasy [175]3 years ago
6 0

Answer:

Alloys and Composites

Explanation:

<u>Drill bits are made of alloys</u> because alloys are very much resistant to corrosion and are created when one or multiple metals are mixed with other elements that are non-metallic in nature. Due to their greater strength, they are used in the power drills in order to create borehole drills at the mining site. Borehole drilling is commonly done in order to understand the sub-surface strata before mining.

<u>The bodies along with the handles of power drills are constructed of composite insulators</u> because within the composites there is the absence of free electrons that has the ability to flow and produce electricity. So they are considered to be used as a good insulator.

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Pls help
Dmitry_Shevchenko [17]

Answer:

The answer would be beryllium

You were probably confused but the correct answer would actually be a beryllium ion.

4 0
2 years ago
Plutonium−239 (t1/2 = 2.41 × 104 yr) represents a serious nuclear waste hazard. if seven half-lives are required to reach a tole
dimulka [17.4K]
The half-life of Plutonium−239, t1/2 is 2.41 × 10⁴<span> yrs

time taken to reach tolerable level = seven half-lives
                                                      = 7 x t1/2
                                                      = 7 x </span>2.41 × 10⁴ yrs
                                                      = 168700 yrs
                                                      = 1.687 x 10⁵ yrs

Hence, the period of time that <span>Plutonium-239 must be stored is </span>1.687 x 10⁵ years.
5 0
3 years ago
Read 2 more answers
Heterotrophs are the consumers in the food chain, particularly the herbivores, carnivores, and omnivores. A. True B. False
scoundrel [369]
The answer is A. True
5 0
3 years ago
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13,000. cm has how many significant figures?
Svet_ta [14]

Answer:

since there is a decimal point at the end, they are all significant figures so the answer is 5

5 0
3 years ago
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What is the molar out of a solution that contains 33.5g of CaCl2 in 600.0mL of water
omeli [17]

Answer:

Here's what I got.

Explanation:

Interestingly enough, I'm not getting

0.0341% w/v

either. Here's why.

Start by calculating the percent composition of chlorine,

Cl

, in calcium chloride, This will help you calculate the mass of chloride anions,

Cl

−

, present in your sample.

To do that, use the molar mass of calcium chloride, the molar mass of elemental chlorine, and the fact that

1

mole of calcium chloride contains

2

moles of chlorine atoms.

2

×

35.453

g mol

−

1

110.98

g mol

−

1

⋅

100

%

=

63.89% Cl

This means that for every

100 g

of calcium chloride, you get

63.89 g

of chlorine.

As you know, the mass of an ion is approximately equal to the mass of the neutral atom, so you can say that for every

100 g

of calcium chloride, you get

63.89 g

of chloride anions,

Cl

−

.

This implies that your sample contains

0.543

g CaCl

2

⋅

63.89 g Cl

−

100

g CaCl

2

=

0.3469 g Cl

−

Now, in order to find the mass by volume percent concentration of chloride anions in the resulting solution, you must determine the mass of chloride anions present in

100 mL

of this solution.

Since you know that

500 mL

of solution contain

0.3469 g

of chloride anions, you can say that

100 mL

of solution will contain

100

mL solution

⋅

0.3469 g Cl

−

500

mL solution

=

0.06938 g Cl

−

Therefore, you can say that the mass by volume percent concentration of chloride anions will be

% m/v = 0.069% Cl

−

−−−−−−−−−−−−−−−−−−−

I'll leave the answer rounded to two sig figs, but keep in mind that you have one significant figure for the volume of the solution.

.

ALTERNATIVE APPROACH

Alternatively, you can start by calculating the number of moles of calcium chloride present in your sample

0.543

g

⋅

1 mole CaCl

2

110.98

g

=

0.004893 moles CaCl

2

To find the molarity of this solution, calculate the number of moles of calcium chloride present in

1 L

=

10

3

mL

of solution by using the fact that you have

0.004893

moles present in

500 mL

of solution.

10

3

mL solution

⋅

0.004893 moles CaCl

2

500

mL solution

=

0.009786 moles CaCl

2

You can thus say your solution has

[

CaCl

2

]

=

0.009786 mol L

−

1

Since every mole of calcium chloride delivers

2

moles of chloride anions to the solution, you can say that you have

[

Cl

−

]

=

2

⋅

0.009786 mol L

−

1

[

Cl

−

]

=

0.01957 mol L

−

This implies that

100 mL

of this solution will contain

100

mL solution

⋅

0.01957 moles Cl

−

10

3

mL solution

=

0.001957 moles Cl

−

Finally, to convert this to grams, use the molar mass of elemental chlorine

0.001957

moles Cl

−

⋅

35.453 g

1

mole Cl

−

=

0.06938 g Cl

−

Once again, you have

% m/v = 0.069% Cl

−

−−−−−−−−−−−−−−−−−−−

In reference to the explanation you provided, you have

0.341 g L

−

1

=

0.0341 g/100 mL

=

0.0341% m/v

because you have

1 L

=

10

3

mL

.

However, this solution does not contain

0.341 g

of chloride anions in

1 L

. Using

[

Cl

−

]

=

0.01957 mol L

−

1

you have

n

=

c

⋅

V

so

n

=

0.01957 mol

⋅

10

−

3

mL

−

1

⋅

500

mL

n

=

0.009785 moles

This is how many moles of chloride anions you have in

500 mL

of solution. Consequently,

100 mL

of solution will contain

100

mL solution

⋅

0.009785 moles Cl

−

500

mL solution

=

0.001957 moles Cl

−

So once again, you have

0.06938 g

of chloride anions in

100 mL

of solution, the equivalent of

0.069% m/v

.

Explanation:

i think this is it

8 0
3 years ago
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