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mariarad [96]
3 years ago
9

When do th macroscopic properties become constant in an equilibrium system?

Chemistry
1 answer:
Ipatiy [6.2K]3 years ago
4 0
When both the force and the reaction rates are equal
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A 1.2516 gram sample of a mixture of caco3 and na2so4 was analyzed by dissolving the sample and completely precipitating the ca
Dennis_Churaev [7]

Answer:

0.009725 moles of H2C2O4

0.009725 moles CaCO3

Mass percentage =  77.77%

Explanation:

<u>Step 1</u>: The balanced equation

2MnO4- +5C2H2O4+6H+ →2Mn2+ +10CO2+8H2O

We can see that for 2 moles of Mno4- consumed , there is 5 moles of C2H2O4 needed and 6 moles H+ to produce 2 moles Mn2+, 10 moles of CO2 and 8 moles of H2O

<u>Step 2</u>: Calculate moles of MnO4-

Molarity = Moles/volume

Moles of Mno4- = Molarity of MnO4- * Volume of Mno4-

Moles of Mno4- = 0.1092M * 35.62 *10^-3 L

Moles of MnO4- = 0.00389 moles

<u>Step 3</u>: Calculate moles of H2C2O4

Since there is needed 5 moles of C2H2O4 to consume 2 moles of MnO4-

then for 0.00389 moles of MnO4-, there is 5/2 *0.00389 = <u>0.009725 moles of H2C2O4</u>

<u />

<u>Step 4:</u> Calculate moles of CaCO3

moles of H2C2O4 = moles CaCO3, therefore, 0.009725 moles H2C2O4 = 0.009725 moles CaCO3

<u>Step 5</u>: Calculate mass of CaCO3

Molar mass of CaCO3 = 100.09 g/mole

Mass of CaCO3 = moles of CaCO3 * Molar mass of CaCO3

Mass of CaCO3 = 0.009725 moles * 100.09 g/mole = 0.9734 g

<u>Step 6</u>: Calculate percentage by weight of CaCO3

Mass of CaCO3 = 0.9734g

Mass of original sample = 1.2516g

Mass percentage = 0.9734/1.2516 *100% = 77.77%

6 0
3 years ago
The human body can get energy by metabolizing proteins, carbohydrates or fatty acids, depending on the circumstances. Roughly sp
Kamila [148]

Answer:

the ratio of the energy the body gets metabolizing each gram of alanine to the energy the body gets metabolizing each gram of glucose is 1.0111

Explanation:

Given the data in the question;

To determine the ratio of the energy the body gets metabolizing each gram of alanine to the energy the body gets metabolizing each gram of glucose, first we get the molar masses of both alanine and glucose

we know that;

Molar mass of alanine ( C₃H₇NO₂ ) = 89.09 g/mol

Molar mass of glucose ( C₆H₁₂O₆ ) = 180.16 g/mol

now, { metabolizing each gram }

moles of alanine = mass taken / molar mass

= 1g / 89.09 g/mol = 1/89.09 moles

moles of glucose = mass taken / molar mass

= 1g / 180.16 g/mol = 1/180.16 moles

In each molecule of alanine, we have 3 atoms  of carbon.

Also, in each molecules of glucose, we have 6 atoms of carbon

so,

number of moles of Carbons in alanine = 3 × 1/89.09 moles = 0.03367

number of moles of Carbons in glucose = 6 × 1/180.16 moles = 0.0333

so ratio of energy will be the ratio of carbon atoms, which is;

⇒ 0.03367 / 0.0333 = 1.0111

Therefore, the ratio of the energy the body gets metabolizing each gram of alanine to the energy the body gets metabolizing each gram of glucose is 1.0111

7 0
3 years ago
Consider the balanced equation below.
Karo-lina-s [1.5K]

The correct option is (a) H₂S : SO₂ = 2 : 2 and O₂ : H₂O = 3 : 2

<h3>What is molar Ratio ?</h3>

Molar ratio also known as stoichiometry is the ratio in which the reactants and products are either formed or reacted in the given equation

the balanced equation is as follows ;

2H₂S + 3O₂ --> 2SO₂ + 2H₂O

molar ratio can be determined by the coefficients of the compounds in the balanced reaction.

coefficient is the number in front of the chemical compound

coefficients for the compounds in this reaction are as follows ;

  • H₂S - 2
  • O₂ - 3
  • SO₂ - 2
  • H₂O - 2

therefore, correct option is (a) H₂S:SO₂ = 2:2 and O₂:H₂O = 3:2

Learn more about molar ratio here ;

brainly.com/question/17920577

#SPJ1

4 0
2 years ago
Using insulate gloves, Ms. Sanders transferred a few pieces of dry ice to a flask and covered it with a balloon. After a few min
gavmur [86]

Answer:

i think the answer is D

Explanation:

5 0
3 years ago
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Water is formed when two hydrogen atoms bond to an oxygen atom. The hydrogen and the oxygen in this example are different A) com
Nata [24]
Hydrogen and oxygen are elements.
8 0
3 years ago
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