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Tomtit [17]
3 years ago
13

What is the value of this expression when c=-4 and d = 10? 1/4(c3+d2)

Mathematics
1 answer:
Mumz [18]3 years ago
3 0
<h2><u>Q</u><u>u</u><u>e</u><u>s</u><u>t</u><u>i</u><u>o</u><u>n</u>:-</h2>

What is the value of this expression when c = -4 and d = 10 ? \frac{1}{4} (c³ + d²)

<h2><u>A</u><u>n</u><u>s</u><u>w</u><u>e</u><u>r</u>:-</h2>

<h3>Given:-</h3>

\frac{1}{4} (c³ + d²) where c = -4 and d = 10

<h3>To Find:-</h3>

The value of the expression \frac{1}{4} (c³ + d²)

<h2>Solution:-</h2>

\frac{1}{4} (c³ + d²) [Given expression]

Now, putting the value of c = -4 and d = 10 , we get,

\frac{1}{4} { (-4)³ + (10)² }

\frac{1}{4} ( -64 + 100 )

\frac{1}{4} ( 36 )

\frac{1}{4} × 36

\bf = \: 9 \: ( Answer )

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Answer:

<u></u>

  • <u>53 seconds.</u>

Explanation:

The text and the model are garbled.

This is the question amended:

<em />

<em>Hyun Woo is riding a ferris wheel. H(t) models his height (in m) above the ground, t seconds after the ride starts. Here, t is entered in radians.</em>

<em>H(t) = -10 cos(2π/150 t)+10</em>

<em />

<em>When does Hyun Woo first reach a height of 16 m?</em>

<em />

<h2>Solution</h2>

<em />

When <em>Hyun Woo reaches a height of 16 m</em> the <em>model </em>states:

  • <em>16 = -10 cos(2π/150 t)+10</em>

<em />

Then you must find the lowest positive value of t that is a solution of the equation.

Solve the equation:

  • <em>16 = -10 cos(2π/150 t)+10</em>

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  • cos(2π/150t) = -0.6

  • 2π/150t = arccos(-0.6)

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  • t = 52.86s ≈ 53 s ← answer
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