All categories

3 years ago

Help?............................

Mathematics

1 answer:

Yanka [14]3 years ago

4 0

Answer:

here you go, translated all points by looking and counting their distance to the x- and y-axis, then switched them and made one negative

but tldr: did it graphically.

the screenshot got the points you need

You might be interested in

Help please i don't Know how to answer this

Artemon [7]

Answer:

a line of symmetry is a line divide an object in to two equal parts. answer is A

3 0

2 years ago

Find the value of x for which the lines rand s are parallel.

erastovalidia [21]

Answer:

x = 12

Step-by-step explanation:

<1 and the 142-deg angle are vertical, so m<1 = 142 deg

The angle measuring 3x + 2 and <1 are same-side interior angles. If the lines are parallel, then those two angles are supplementary.

3x + 2 + 142 = 180

3x + 144 = 180

3x = 36

x = 12

3 0

3 years ago

Are the solutions correct?

Aloiza [94]

Answer:

First one is wrong. x should be 16.

Second one is not completely visible, so cannot say.

Step-by-step explanation:

In the last step, the divison by 4 yields:

x/16 = 1, so x = 16

4 0

3 years ago

Linear or nonlinear

Wittaler [7]

Answer:

Linear

Step-by-step explanation:

It increases by a steady rate, so it is linear.

5 0

3 years ago

The probability that an egg on a production line is cracked is 0.01. Two eggs are selected at random from the production line. F

musickatia [10]

Answer:

$P(X \geq 1)=1-P(X$

$P(X=0)=(2C0)(0.01)^0 (1-0.01)^{2-0}=0.9801$

And replacing we got:

$P(X \geq 1) = 1-0.9801 = 0.0199$

Step-by-step explanation:

Let X the random variable of interest "number of craked eggs", on this case we now that:

$X \sim Binom(n=2, p=0.01)$

The probability mass function for the Binomial distribution is given as:

$P(X)=(nCx)(p)^x (1-p)^{n-x}$

Where (nCx) means combinatory and it's given by this formula:

$nCx=\frac{n!}{(n-x)! x!}$

And we want to find this probability:

$P(x \geq 1)=1-P(X$

And we can find the probability:

$P(X=0)=(2C0)(0.01)^0 (1-0.01)^{2-0}=0.9801$

And replacing we got:

$P(X \geq 1) = 1-0.9801 = 0.0199$

5 0

2 years ago