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3 years ago

12

A restaurant can serve a maximum of 70 patrons. There are 47 now being served. Write an inequality to find out how many people m

ay be served.

1 answer:

Fiesta28 [93]3 years ago

8 0

70-47=23
I think this is what you are talking about

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When Belinda asked him to what pages his book was opened, he replied that the product of the facing pages was 87,912. To what pa

Liono4ka [1.6K]

Answer:

His book was opened at Page no.296 and Page no.297

Step-by-step explanation:

Let the page number of one page be x

Page number of page facing page no. x = x+1

We are given that the product of the facing pages was 87,912.

So, x(x+1)=87912

$x^2+x=87912$

$x^2+x-87912=0$

$x^2-296x+297x-87912=0$

$x(x-296)+297(x-296)=0$

(x+297)(x-296)=0

x=296,-297

Since Page no. cannot be negative

So, x=296

x+1=296+1=297

So, his book was opened at Page no.296 and Page no.297

5 0

3 years ago

A track star runs two races on a certain day. The probability thathe wins the first race is 0.7, the probability that he wins th

NARA [144]

Answer:

a) 80% probability that he wins at least one race.

b) 30% probability that he wins exactly one race.

c) 20% probability that he wins neither race.

Step-by-step explanation:

We solve this problem building the Venn's diagram of these probabilities.

I am going to say that:

A is the probability that he wins the first race.

B is the probability that he wins the second race.

C is the probability that he does not win any of these races.

We have that:

$A = a + (A \cap B)$

In which a is the probability that he wins the first race but not the second and $A \cap B$ is the probability that he wins both these races.

By the same logic, we have that:

$B = b + (A \cap B)$

The probability that he wins both races is 0.5.

This means that $A \cap B = 0.5$

The probability that he wins the second race is 0.6

This means that $B = 0.6$

$B = b + (A \cap B)$

$0.6 = b + 0.5$

$b = 0.1$

The probability that he wins the first race is 0.7.

This means that $A = 0.6$

$A = a + (A \cap B)$

$0.7 = a + 0.5$

$a = 0.2$

A) he wins at least one race.

This is

$P = a + b + (A \cap B) = 0.2 + 0.1 + 0.5 = 0.8$

There is an 80% probability that he wins at least one race.

B) he wins exactly one race.

This is

$P = a + b = 0.2 + 0.1 = 0.3$

There is a 30% probability that he wins exactly one race.

C) he wins neither race

Either he wins at least one race, or he wins neither. The sum of these probabilities is 100%.

From a), we have that there is an 80% probability that he wins at least one race.

So there is a 100-80 = 20% probability that he wins neither race.

6 0

3 years ago

Determine the rate and the unit rate. $18 for 6 volleyballs

Nadusha1986 [10]

Answer:

3.00$ is the answer

5 0

3 years ago

Theo earns a base salary plus commission. At the end of September, he was paid $3,835.25 based on his monthly sales of $12,850.

hodyreva [135]

Theo's base salary using a simultaneous equation approach is $2,996.22 .

In order to determine the base salary of Theo, we can express the two earnings and sales amounts using simultaneous equation, that we would solve to arrive at the base salary

Bear in mind that total earnings are determined as base salary plus commission

Let X be the base salary

Let R be the rate of commission

commission =sales*rate of commission

When earnings were $3,835.25 and sales is $12,850, we have the below equation:

X+(12,850*R)=3,835.25

X+12850R=3,835.25 .................... equation (1)

When earnings were $3,641 and sales is $9,875, we have the below equation:

X+(9,875*R)=3641

X+9875R=3641 ......................... equation (2)

subtract equation 2 from 1

2975R=194.25

R=194.25/2975

R=commission rate=6.52941176470588%

substitute for R in equation 1 to arrive at X(base salary)

X+(12850*6.52941176470588%)=3,835.25

X=3,835.25-(12850*6.52941176470588%)

X=base salary=$2,996.22

Find further guide on simultaneous equation in the link below:

brainly.com/question/6597041

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7 0

2 years ago

2865 students participated in a competitive exam. There were 60 rooms in the

sladkih [1.3K]

47 students per room, 45 weren’t in a room

5 0

3 years ago