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bekas [8.4K]
3 years ago
9

Around which line would the following cross-section need to be revolved to create a sphere?

Mathematics
1 answer:
rjkz [21]3 years ago
4 0

Answer:

it should be y=1

Step-by-step explanation:

I hope this help

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A photograph was enlarged to a width of 15 inches. If the scale factor was 3 /2 , what was the width of the original photograph?
andre [41]
If the width is 15, and the scale factor from width to length is 3:2, then you will have to divide 15 by 3 to get your original width.
15/3 = 5.
5 is your original width.
6 0
3 years ago
What is the average size of a toothpick
Tanzania [10]
About less than 3 inches :)
4 0
3 years ago
Read 2 more answers
Can someone please help me
mrs_skeptik [129]

Step-by-step explanation:

5x=4x+12(corresponding angle)

5x-4x=12

x=12

if it is correct answer then please follow me

6 0
3 years ago
13. In A ABC, if m BF is an angle bisector, find<br> m
Tresset [83]

If in the triangle ABC , BF is an angle bisector and ∠ABF=41° then angle m∠BCE=8°.

Given that m∠ABF=41° and BF is an angle bisector.

We are required to find the angle m∠BCE if BF is an angle bisector.

Angle bisector basically divides an angle into two parts.

If BF is an angle bisector then ∠ABF=∠FBC by assuming that the angle is divided into two parts.

In this way ∠ABC=2*∠ABF

∠ABC=2*41

=82°

In ΔECB we got that ∠CEB=90° and ∠ABC=82° and we have to find ∠BCE.

∠BCE+∠CEB+EBC=180  (Sum of all the angles in a triangle is 180°)

∠BCE+90+82=180

∠BCE=180-172

∠BCE=8°

Hence if BF is an angle bisector then angle m∠BCE=8°.

Learn more about angles at brainly.com/question/25716982

#SPJ1

4 0
2 years ago
I tried solving it but I everytime I follow how its suppose to go, I dont get the right answer.
77julia77 [94]

Answer:

B. 64.9

Step-by-step explanation:

A graphing calculator or spreadsheet can fit these points with an exponential curve. An appropriate answer for x=14 is about 73.3.

_____

<em>Comment on the answer choices</em>

The closest answer that makes any sense is 64.9. Often these problems are worked by someone who uses inappropriate rounding of intermediate results. I haven't found the magic set of numbers to get 64.9. About the lowest I can get is 66.7, using 0.0037·e^(0.7x).

8 0
3 years ago
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