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bekas [8.4K]
3 years ago
9

Around which line would the following cross-section need to be revolved to create a sphere?

Mathematics
1 answer:
rjkz [21]3 years ago
4 0

Answer:

it should be y=1

Step-by-step explanation:

I hope this help

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Step-by-step explanation:

Theory :

Equation of line is given as y = mx + c.

Where, m is slope and c is y intercepted.

Slope of given line : y = \frac{2}{3}x+1 is m= \frac{2}{3}

We know that line : y = \frac{2}{3}x+1 is parallel to equation of target line.

therefore, slope of target line will be \frac{2}{3}.

we write equation of target line as y= \frac{2}{3}x+c

Now, It is given that target line passes through point ( -5,-2)

hence, point ( -5,-2) satisfy the target line's equation.

we get,

y= \frac{2}{3}x+c

-2= \frac{2}{3} \times -5+ c

-5= \frac{-10}{3}+c

c= \frac{-5}{3}

thus, Equation of line is y=Equation of line is y=\frac{2}{3}x+\frac{-5}{3}

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