Can some one plz help again?
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Answer:
And the 90% confidence interval would be given (0.0942;0.09978).
We are confident at 90% that the difference between the two proportions is between
Step-by-step explanation:
Previous concepts
A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".
The margin of error is the range of values below and above the sample statistic in a confidence interval.
Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".
represent the real population proportion female for Biology
represent the estimated proportion female for biology
is the sample size for A
represent the real population proportion female for calculus AB
represent the estimated proportion female for Calculus AB
is the sample size required for B
represent the critical value for the margin of error
The population proportion have the following distribution
The confidence interval for the difference of two proportions would be given by this formula
For the 90% confidence interval the value of and
, with that value we can find the quantile required for the interval in the normal standard distribution.
And replacing into the confidence interval formula we got:
And the 90% confidence interval would be given (0.0942;0.09978).
We are confident at 90% that the difference between the two proportions is between