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2 years ago

5

Can some one plz help again?

1 answer:

LekaFEV [45]2 years ago

6 0

Answer:

Associative property of addition

Step-by-step explanation:

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HELP ASAP!! Identify the matrix transformation of ΔPQR, which has coordinates P(−5, −2),Q(−6, −3), and R(−2, −3), for reflection

podryga [215]

Answer:

Matrix transformation = $\left[\begin{array}{ccc}-1&0\\0&1\end{array}\right]$

Vertices of the new image: P'= (5,-2), Q'= (6,-3), R'= (2,-3)

Step-by-step explanation:

Transformation by reflection will produce a new congruent object in different coordinate. Reflection to y-axis made by multiplying the x coordinate with -1 and keep the y coordinate unchanged. The matrix transformation for reflection across y-axis should be: $\left[\begin{array}{ccc}-1&0\\0&1\end{array}\right]$ .

To find the coordinate of the vertices after transformation, you have to multiply the vertices with the matrix. The calculation of the each vertice will be:

P'= $\left[\begin{array}{ccc}-1&0\\0&1\end{array}\right]$ $\left[\begin{array}{ccc}-5\\-2\end{array}\right]$ = (5,-2)

Q'= $\left[\begin{array}{ccc}-1&0\\0&1\end{array}\right]$ $\left[\begin{array}{ccc}-6\\-3\end{array}\right]$ = (6,-3)

R'= $\left[\begin{array}{ccc}-1&0\\0&1\end{array}\right]$ $\left[\begin{array}{ccc}-2\\-3\end{array}\right]$ = (2,-3)

3 0

3 years ago

Which of the following is a solution of x2 + 6x = −18? x = 3 − 3i x = −3 + 3i x = −6 + 3i x = 6 − 3i

Marina86 [1]

Step 1 ) Move all terms right side of the equation.

$\displaystyle\ x^{2} + 6x = -18$

$\displaystyle\ x^{2} + 6x + 18 = -18 + 18$

$\displaystyle\ x^{2} +6x + 18 = 0$

Step 2 ) Apply quadratic formula. (Note: There are 2 solutions)

$\displaystyle\ x^{2} +6x + 18 = 0$

$\displaystyle\ x = \frac{-b\sqrt{b^{2}-4ac}}{2a}, \displaystyle\ x = \frac{-b-\sqrt{b^{2}-4ac}}{2a}$

$\displaystyle\ x = \frac{-6+\sqrt{6^{2}-4 * 18}}{2} , \displaystyle\ x = \frac{-6-\sqrt{6^{2}-4*18}}{2}$

$\displaystyle\ x = \frac{-6+6i}{2}$ ,

$\displaystyle\ x = \frac{-6-6i}{2}$

Step 3 ) Simplify.

$\displaystyle\ x = \frac{-6+6i}{2}$ ,

$\displaystyle\ x = \frac{-6-6i}{2}$

$\displaystyle\ x = -3+ 3i$ ,

$\displaystyle\ x = -3 - 3i$

Since the options only provide one of the answer we found, the answer is...

$\displaystyle\ x = -3 - 3i$

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- <em>Marlon Nunez</em>

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true

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true

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