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postnew [5]
3 years ago
15

All elements are composed of extremely small particles called

Physics
1 answer:
Tasya [4]3 years ago
8 0
The answer is Atoms they are in every single element
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A 150 kg line backer sacks the 120 kg quarterback. With what force is the quarterback sacked if the line backer has an accelerat
Gekata [30.6K]

Answer:

The force required to move the quarterback with linebacker is <u>1215 N</u>

Explanation:

\text { Mass of linebacker } \mathrm{m}_{2}=150 \mathrm{kg}

\text { Mass of quarterback } \mathrm{m}_{2}=120 \mathrm{kg}

\text { Moved at an acceleration }(a)=4.5 \mathrm{m} / \mathrm{s}^{2}

Using Newton's second law, it is established that  F = Ma

Where F is net force acting on the system, a is the acceleration and M is mass of the two object \left(m_{1}+m_{2}\right)

Now consider both \mathrm{m}_{1} \text { and } \mathrm{m}_{2}as a system, so net force acting on the system is \text { Force }=\left(m_{1}+m_{2}\right) a

Substitute the given values in the above formula,

\text { Force }=(150+120) \mathrm{kg} \times 4.5 \mathrm{m} / \mathrm{s}^{2}

\text { Force }=270 \mathrm{kg} \times 4.5 \mathrm{m} / \mathrm{s}^{2}

Force = 1215 N

<u>1215 N </u>is the force required to move the quarterback with linebacker.

5 0
4 years ago
Find the speed for Barkely, the dog, if he runs 5.5 miles in 3 hours
amm1812

Answer: B

Explanation:

5.5/3

6 0
3 years ago
Suppose a 96.10 kg hiker has ascended to a height of 1841 m above sea level in the process of climbing Mt. Washington. By what p
lbvjy [14]

Answer:

0.029%

Explanation:

Weight on the surface is given by,

F_W = mg = (96.1Kg)(9.8m/s^2)=941.78N

The acceleration due to gravity at given height is,

g_h=\frac{gR^2}{R+h^2}

The weight in another height is equal to

F_h=mg_h

F_h= m*\frac{gR^2}{R+h^2}

F_h = \frac{F_WR^2}{(R+h)^2}

F_h=\frac{(941.78)(6.371*10^6)}{(6.371*10^6+1841)}

F_h = 941.50N

The change of the Weight is,

\frac{F-F_h}{F}*100=\frac{941.78-941.50}{941.78}*100=0.029\%

6 0
3 years ago
Find the length of a microscope having magnifying power 100, if the focal lengths of the objective and eye piece are 2 cm and 5
sp2606 [1]

Answer:

   L = 40 cm

Explanation:

A microscope is an optical instrument built by two lenses in such a way that the image of the first is formed within the distance of the other (eyepiece), so that the latter creates an enlarged virtual image of the object, for which the magnification of the microscope is the same to the multiplication of the magnification of each lens

    M = - L / f₀ (25 cm /f_{e})

where fo and fe are the focal lengths of the objective and eyepiece, 25 cm is the near vision distance and L is the length of the microscope

     L = - M f_{o} f_{e} / 25

let's calculate

     L = - (-100) 2 5/25

      L = 40 cm

7 0
3 years ago
If I measure the current to be 0.5 A and the voltage is 4.5 V. What is my Power?
Korvikt [17]
As we know that P=IV so P = (0.5A)(4.5V)
                                            P= 2.25 watt
6 0
3 years ago
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