All categories

3 years ago

What is the name given to the force exerted by the first object on a second object

1 answer:

6 0

Soppose the 1 object is A and 2 is B then the force exerted by A on B is FAB and the force exerted on body B on A is -FAB.

You might be interested in

You do 45.0 joules of work and 3.00 seconds how much power do you use

Arada [10]

Answer:

15 watt

Explanation:

Power is the rate at which work is done.

This means you divide the work done with the amount of time used to perform the work.

The formula for Power is : P = W/t where;

W= work done in J = 45

t= time in seconds = 3 sec

P= 45/ 3 = 15 watt

8 0

2 years ago

The efficiency of a machine is always less than 100% because part of the energy input is used to

Travka [436]

Answer:

C. Overcome Friction

Explanation:

When using any machine usually those with moving parts, you may notice heat forming near the areas where most movement occurs. As friction continues, more energy is used up and released as heat. For that reason, the efficiency of a machine will forever be less than 100%

5 0

2 years ago

A ball is thrown vertically upwards with an initial velocity of 20.00 m/s. Neglecting air resistance, how long is the ball in th

algol [13]

Answer:

1) The greatest height attained by the ball equals 20.387 meters.

2) The time it takes for the ball to reach 15 meters approximately equals 1 second.

Explanation:

The greatest height will be attained when the ball stop's in the air and starts falling back to the earth.

thus using third equation of kinematics we obtain the height attained as

$v^2=u^2+2as$

where

'v' is the final speed of the ball

'u' is the initial speed of the ball

'a' is the acceleration that the ball is under which in this case equals 9.81 $m/s^{2}$

's' is the distance it covers

Thus for maximum height applying the values in the equation we get

$0=20^{2}-2\times 9.81\times h\\\\\therefore h=\frac{20^{2}}{2\times 9.81}=20.387meters$

Using the same equation we can find the speed of the ball when it reaches 15 meters of height as

$v^2=20^{2}-2\times 9.81\times 15\\\\v^{2}=105.7\\\\\therefore v=10.28m/s$

the time it takes to reduce the velocity to this value can be found by first equation of kinematics as

$v=u+at\\\\t=\frac{v-u}{a}\\\\t=\frac{10.28-20}{-9.81}=0.991seconds\approx 1second$

4 0

3 years ago

A 2,500 kg car moves at 15 m/s^2; 15m/s^2 is the (blank) of the car.

Neporo4naja [7]

A. Acceleration.
acceleration is m/s^2. speed is m/s

7 0

2 years ago

Is it possible for surfers to use dynamite to produce water waves that are suitable for surfing

hammer [34]

if they had a suitable amount to cause an interruption in the waves so huge and vast that it makes waves..... it depends because you can have any amount and get different results any day though

hope this helps plz mark me brainliest

7 0

3 years ago