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ivolga24 [154]
2 years ago
10

Which class of hazards is characterized by thermal and mechanical hazards in the form of blast pressure waves, shrapnel and frag

mentation, and incendiary thermal effects
Physics
1 answer:
Mkey [24]2 years ago
3 0

Class 1 (Explosives) is the class of hazards that is characterized by thermal and mechanical hazards in the form of blast pressure waves, shrapnel and fragmentation, and incendiary thermal effects.

There are different classes of Hazards

Class 1 - Explosives

Class 2 - Gases

Class 3 - Flammable liquids

Class 4 - Flammable solids

Class 5 - Oxidizers

Class 6 - Toxic materials

Class 7 - Radioactive materials

Class 8 - Corrosive materials

Class 9 - Miscellaneous dangerous goods

Any substance or item, including<u> a gadget</u>, that is intended to function by explosion or that, <u>through a chemical reaction</u> inside itself, is capable of functioning similarly even if not intended to function by explosion, falls within the category of explosive materials (class 1).

Hence, Class 1 (Explosives) is the class of hazards that is characterized by thermal and mechanical hazards.

Learn more about Types of Hazards here brainly.com/question/13941479

#SPJ4

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If f(x) = -3x +4 and g(x) = 2, solve for the value of x for<br>which (fx) = g(x) is true.​
maksim [4K]

Answer:

x=-\frac{2}{3}

Explanation:

Let:

f(x)=-3x+4\\\\And\\\\g(x)=2

We need to know for which value of x the function f(x) is equal to g(x):

f(x)=g(x)

Therefore, we need to solve for the previous equation for x:

Replacing the values of f(x) and g(x):

-3x+4=2

Subtract 4 from both sides:

-3x+4-4=2-4\\\\-3x=-2

Multiply both sides by -1

-3x(-1)=-2(-1)\\\\3x=2

Divide both sides by 3:

\frac{3x}{3} =\frac{2}{3} \\\\x=\frac{2}{3}

Therefore the value of x for which f(x)=g(x) is x=\frac{2}{3}.

Verify the result:

-3(\frac{2}{3} )+4=2\\\\-2+4=2\\\\2=2

4 0
4 years ago
Shareen finds that when she drives her motorboat upstream she can travelwith a speed of only 8 m/s, while she moves with a speed
ANEK [815]

Let vb be the velocity of the motorboat and let vs be the velocity of the stream.

We know that when she drives upstream the velocity is 8 m/s, in this scenario the velocities point in opposite directions, then we have the equations:

v_b-v_s=8

When she drives downstream the velocites point in the same direction then we have the equation:

v_b+v_s=12

hence we have the system of equations:

\begin{gathered} v_b-v_s=8 \\ v_b+v_s=12 \end{gathered}

Solving the first equation for the velocity of the boat we have:

v_b=8+v_s

Plugging this in the second equation we have:

\begin{gathered} 8+v_s+v_s=12 \\ 2v_s=4 \\ v_s=\frac{4}{2} \\ v_s=2 \end{gathered}

Therefore, the velocity of the stream is 2 m/s

5 0
1 year ago
A bowling ball of mass m=1.7kg is launched from a spring compressed by a distance d=0.31m at an angle of theta=37 measured from
vodomira [7]

Answer:

k = 1 700.7 N/m

v0 = 9.8 m/s^2

Explanation:

Hello!

We can answer this question using conservation of energy.

The potential energy of the spring (PS) will transform to kinetic energy (KE) of the ball, and eventually, when the velocity of the ball is zero, all that energy will be potential gravitational (PG) energy.

When the kinetic energy of the ball is zero, that is, when it has reached its maximum heigh, all the potential energy of the spring will be equal to the potential energy of the gravitational field.

PS = (1/2) k x^2  <em>where x is the compresion or elongation of the spring</em>

PG = mgh

a)

Since energy must be conserved and we are neglecting any energy loss:

PS = PG

Solving for k

k = (2mgh)/(x^2) = ( 2 * 1.7 * 9.81 * 4.9 Nm)/(0.31^2 m^2)

k = 1 700.7 N/m

b)

Since the potential energy of the spring transfors to kinetic energy of the ball we have that:

PS = KE

that is:

(1/2) k x^2 = (1/2) m v0^2

Solving for v0

v0 = x √(k/m) = (0.31 m ) √( 1 700.7 N/m / 1.7kg)

v0 = 9.8 m/s^2

8 0
3 years ago
What is the frequency of a tuning fork that vibrates 518 times in 3.50 s?
Serga [27]

Given:

The number of vibrations of the tuning fork is,

51\text{8 times}

in,

t=3.50\text{ s}

To find:

The frequency of the fork

Explanation:

The frequency is the number of vibrations in 1 second

The frequency for the given fork is,

\begin{gathered} \frac{The\text{ total vibrations}}{The\text{ time}} \\ =\frac{518}{3.50} \\ =148\text{ Hz} \end{gathered}

Hence, the frequency is 148 Hz.

7 0
1 year ago
In regard to exercise, which of the following statements about safety consideration is correct?
Triss [41]

Answer:

the correct answer is

D.Remaining well-hydrated while exercising is best

8 0
3 years ago
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