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vova2212 [387]
3 years ago
14

Which of the following is true for the equilibrium constant of a reaction?

Chemistry
1 answer:
CaHeK987 [17]3 years ago
4 0

Answer:

The correct answer is <em>It is a ratio of the concentrations in a reaction.</em>

Explanation:

⇒ It is a ratio of the concentrations in a reaction.

This sentence is true because the equilibrium constant is calculated from the product of the concentration of the reaction products divided into the product of the concentrations of the reactants, each concentration raised by the stoichiometric coefficient. For example, for the following reaction:

aA + bB → cC + dD

The equilibrium constant is expressed as:

K = \frac{[C]^{c}[D]^{d}  }{[A]^{a} [B]^{b} }

⇒ It remains the same at different temperatures.

The sentence is false because the equilibrium constant changes with the temperature. In general, an endothermic reaction is favored by the increment of temperature (the equilibrium shifts to the right side) and disfavored with the decrease in temperature (shifts to the left).

⇒ It is represented by the symbol H.

This sentence is false because the equilibrium constant is represented with the letter K.

⇒ Its value is always close to 1.

It is not true because the equilibrium constant can be a number below or above 1.

K < 1 ⇒ there is more concentration of reactants at equilibrium

K > 1 ⇒ there is more concentration of products at equilibrium

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Calculate the amount of heat that must be absorbed by 10.0 g of ice at –20°C to convert it to liquid water at 60.0°C. Given: spe
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Answer:

The amount of heat to absorb is 6,261 J

Explanation:

Calorimetry is in charge of measuring the amount of heat generated or lost in certain physical or chemical processes.

The total energy required is the sum of the energy to heat the ice from -20 ° C to ice of 0 ° C, melting the ice of 0 ° C in 0 ° C water and finally heating the water to 60 ° C.

So:

  • Heat required to raise the temperature of ice from -20 °C to 0 °C

Being the sensible heat of a body the amount of heat received or transferred by a body when it undergoes a temperature variation (Δt) without there being a change of physical state (solid, liquid or gaseous), the expression is used:

Q = c * m * ΔT

Where Q is the heat exchanged by a body of mass m, made up of a specific heat substance c and where ΔT is the temperature variation (ΔT=Tfinal - Tinitial).

In this case, m= 10 g, specific heat of the ice= 2.1 \frac{J}{g*C} and ΔT=0 C - (-20 C)= 20 C

Replacing: Q= 10 g*2.1 \frac{J}{g*C} *20 C and solving: Q=420 J

  • Heat required to convert 0 °C ice to 0 °C water

The heat Q necessary to melt a substance depends on its mass m and on the called latent heat of fusion of each substance:

Q= m* ΔHfusion

In this case, being 1 mol of water= 18 grams: Q= 10 g*6.0 \frac{kJ}{mol} *\frac{1 mol of water}{18 g}= 3.333 kJ= 3,333 J (being kJ=1,000 J)

  • Heat required to raise the temperature of water from 0 °C to 60 °C

In this case the expression used in the first step is used, but being: m= 10 g, specific heat of the water= 4.18 \frac{J}{g*C} and ΔT=60 C - (0 C)= 60 C

Replacing: Q= 10 g*4.18 \frac{J}{g*C} *60 C and solving: Q=2,508 J

Finally, Qtotal= 420 J + 3,333 J + 2,508 J

Qtotal= 6,261 J

<u><em> The amount of heat to absorb is 6,261 J</em></u>

<u><em></em></u>

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