Hey there!:
Molar mass MgCl2 = 95.2110 g/mol
So:
1 mole MgCl2 -------------- 95.2110 g
moles MgCl2 ---------------- 319 g
moles MgCl2 = 319 * 1 / 95.2110
moles MgCl2 = 319 / 95.2110
=> 3.350 moles of MgCl2
Hope that helps!
Answer:
44.7 degree (3 s.f)
Explanation:
mass of water = 4.10Kg
Initial temperature = 37.5C
Final temperature = x
Heat = 125 kJ = 125000 J
Specific heat capacity = 4180 J/kg°C
These parameters are given by:
H = MCΔT
ΔT = H / MC
ΔT = 125000 / (4.10 * 4180)
ΔT = 7.294
ΔT = T2 - T1
T2 = ΔT + T1
T2 = 7.294 + 37.5
T2 = 44.794 = 44.7 degree (3 s.f)
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d answer is correct that help
Mars........................