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3 years ago

15

How were the Earth’s Layers formed?

2 answers:

olchik [2.2K]3 years ago

8 0

Answer:

yes here

Explanation:

The major layers of the Earth, starting from its center, are the inner core, the outer core, the mantle, and the crust. These layers formed as the building blocks of Earth, known as planetesimals, collided and collapsed under their own gravity around 4.5 billion years ago

Llana [10]3 years ago

5 0

The major layers of the Earth, starting from its center, are the inner core, the outer core, the mantle, and the crust. These layers formed as the building blocks of Earth, known as planetesimals, collided and collapsed under their own gravity around 4.5 billion years ago.

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How many mols of a 3M NaOH solution are in 1L of the solution?

Alex

To calculate this, we need the Molarity formula. This formula tell us that Molarity, which is a concentration unit, is equal to the number of moles divided by the volume. In this question we already have the Molarity and the Volume, so let's build our equation:

C = n/V (You can see Molarity with the letter "C" because it means concentration)

3 = n/1

n = 1 * 3

n = 3 moles of NaOH

6 0

1 year ago

The combustion of 0.570 g of benzoic acid (ΔHcomb = 3,228 kJ/mol; MW = 122.12 g/mol) in a bomb calorimeter increased the tempera

torisob [31]

Answer:

The temperature change from the combustion of the glucose is 6.097°C.

Explanation:

Benzoic acid;

Enthaply of combustion of benzoic acid = 3,228 kJ/mol

Mass of benzoic acid = 0.570 g

Moles of benzoic acid = $\frac{0.570 g}{122.12 g/mol}=0.004667 mol$

Energy released by 0.004667 moles of benzoic acid on combustion:

$Q=3,228 kJ/mol \times 0.004667 mol=15.0668 kJ=15,066.8 J$

Heat capacity of the calorimeter = C

Change in temperature of the calorimeter = ΔT = 2.053°C

$Q=C\times \Delta T$

$15,066.8 J=C\times 2.053^oC$

$C=7,338.92 J/^oC$

Glucose:

Enthaply of combustion of glucose= 2,780 kJ/mol.

Mass of glucose=2.900 g

Moles of glucose = $\frac{2.900 g}{180.16 g/mol}=0.016097 mol$

Energy released by the 0.016097 moles of calorimeter combustion:

$Q'=2,780 kJ/mol \times 0.016097 mol=44.7491 kJ=44,749.1 J$

Heat capacity of the calorimeter = C (calculated above)

Change in temperature of the calorimeter on combustion of glucose = ΔT'

$Q'=C\times \Delta T'$

$44,749.1 J=7,338.92 J/^oC\times \Delta T'$

$\Delta T'=6.097^oC$

The temperature change from the combustion of the glucose is 6.097°C.

6 0

3 years ago

What are two ways to change the state of a substance.

kirill [66]

Well you can freeze it to make it a solid then you can melt it to make it a liquid
I hope this helps you.

8 0

3 years ago

Read 2 more answers

Which letter indicates the asthenosphere

Andrews [41]

Answer:

q

Explanation:

8 0

3 years ago

What is the correct ratio of the atoms of the two elements present in a sample of the compound copper chloride, CuCl2?

Aleonysh [2.5K]

The correct ratio of the atoms of the two elements in the sample of copper chloride compound would be 1:2.

<h3>Atoms of elements</h3>

Copper chloride has a chemical formula, $CuCl_2$ .

Thus, an atom of copper, Cu, combines with 2 atoms of chlorine, Cl.

The 2 chlorine atoms are recipients of an electron each from the copper atom which happens to have 2 electrons in its outermost valence shell.

Therefore, the ratio of copper to chlorine atoms in the compound is 1:2.

More on atoms of elements can be found here: brainly.com/question/15173445

#SPJ1

8 0

2 years ago