I’ll give brainlest

Explain why having a thick, heavy chimney is a better idea than a thin, metal chimney for heating a home all winter long, especi

MA_775_DIABLO [31]

The major idea behind why having a thick, heavy chimney over a thin, metal chimney for heating a home for a longer period is because it retains a lot of heat and this means energy saving, hence it fuel efficient and cost effective

A metal is a good conductor of heat, this property will make it easily give out head that is needed to the surrounding especially at night, therefore a thick chimney especially made from clay material will be a better choice over a thin metal

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6 0

3 years ago

You start with 1 L of CO2 at standard temperature and pressure in a closed container. If you raise the temperature of the gas, t

pychu [463]

Answer:

Increase

Explanation:

According to Gay-Lussac Law,

The pressure of given amount of a gas is directly proportional to its temperature at constant volume and number of moles.

Mathematical relationship:

P₁/T₁ = P₂/T₂

If the initial temperature and pressure is standard,

Pressure = 1 atm

Temperature = 273.15 K

then we increase the temperature to 400.0 K, The pressure will be,

1 atm / 273.15 K = P₂/400.0K

P₂ = 1 atm × 400.0 K / 273.15 K

P₂ = 400.0 atm. K /273.15 K

P₂ = 1.46 atm

Pressure is also increase from 1 atm to 1.46 atm.

8 0

3 years ago

As a chemist for an agricultural products company, you have just developed a new herbicide,"Herbigon," that you think has the po

Ganezh [65]

Answer:

pH = 2.03

Explanation:

The pH can be calculated using the following equation:

$pH = -log [H_{3}O^{+}]$ (1)

The concentration of H₃O⁺ is calculated using the dissociation constant of the next reaction:

CH₃COOH + H₂O ⇄ CH₃COO⁻ + H₃O⁺

1.00 M

$K_{a} = \frac{[CH_{3}COO^{-}][H_{3}O^{+}]}{[CH_{3}COOH]}$

Solving the above equation for H₃O⁺, we have:

$[H_{3}O^{+}] = \frac{Ka*[CH_{3}COOH]}{[CH_{3}COO^{-}]}$ (2)

The dissociation constant is equal to:

$pKa = -log(Ka) \rightarrow Ka = 10^{-pKa} = 10^{-4.76} = 1.74 \cdot 10^{-5}$

Now, by solving the equation of the solubility product for Herbigon, we can find [CH₃COO⁻]:

CH₃COOX ⇄ CH₃COO⁻ + X⁺

5.00x10⁻³ M

$K_{sp} = [CH_{3}COO^{-}][X^{+}]$

$[CH_{3}COO^{-}] = \frac{K_{sp}}{[X^{+}]} = \frac{9.40 \cdot 10^{-6}}{5.00 \cdot 10^{-3}} = 1.88 \cdot 10^{-3} M$

By entering the values of [CH₃COO⁻] and Ka, into equation (2) we can calculate [H₃O⁺]:

$[H_{3}O^{+}] = \frac{1.74 \cdot 10^{-5}*[1.00]}{[1.88 \cdot 10^{-3}]} = 9.26 \cdot 10^{-3} M$

Hence, the pH is:

$pH = -log [H_{3}O^{+}] = -log [9.26 \cdot 10^{-3}] = 2.03$

Therefore, the pH must be 2.03 to yield a solution in which the concentration of X⁺ is 5.00x10⁻³M.

I hope it helps you!

6 0

4 years ago

Hurry I need help quickThe table shows the mass and boiling point of some substances. Boiling Point of Substances Mass (kg) Boil

Talja [164]

I am probably wrong but I would think 900. I wouldn’t submit that without somebody backing me up though.

4 0

3 years ago

Read 2 more answers

What is the physical property to all of these (pls answer I’ll give brainliest)

Sav [38]

Answer:

Explanation:

Brittleness : The ability of an object to break apart or shatter easily

Ductility: The ability of a substance to be stretched out into a long wire-like shape.

Lustre: the ability of an object to reflect light.

Malleability is a substance's ability to deform under pressure

The melting point of ice is 0°C. The melting point of a solid is the same as the freezing point of the liquid

Solubility is the relative ability of a solute to dissolve into a solvent.

solid: Has a definite shape and volume.

liquid: Has a definite volume, but take the shape of the container.

gas: Has no definite shape or volume. change of state

The resistance of a liquid to flowing is its viscosity.

Let me Know if i missed somethin!!! :) Hope this Helped!!!

4 0

3 years ago

Read 2 more answers