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Vesna [10]
3 years ago
9

Will give brainliest! Please help!!

Mathematics
1 answer:
Lorico [155]3 years ago
3 0

Answer:1.16 to 30 times     2.8 to 30 times     3.less likely to land on c

4.125 times       5.Yes

Step-by-step explanation:The probability is unknown but an educated guess.

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Answer:

the perimeter of a square is 4a.. where (a) is one side

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14=2x+54

2x= -40

x= -20

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What is the range of the function y=^3 sqrt x+8
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y=\sqrt[3]{x}+8\ or\ y=\sqrt[3]{x+8}\\\\The\ range\ and\ domain:\ All\ real\ numbers
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3 years ago
Math 1125 – Unit 1 ~ Gunkelman Practice for Section 1.5 The Basics of Graphing Prep Skills The table represents the Seven Summit
marta [7]

According to the table, the highest mountain in Africa is Mt. Kilimanjaro with 19,340 feet in height. The highest mountain in Antarctica is Vinson Massif with 16,864 feet in height.

Then, we subtract

19,340-16,864=2,476<h2>The difference between the heights of the highest mountain in Africa and the highest mountain in Antarctica is 2,476 feet.</h2>
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2 years ago
Jen wants to tile the floor of her kitchen. The floor is rectangular and measures 12 feet by 8 feet. If it costs $2.50 per squar
Keith_Richards [23]
I hope this helps you

8 0
3 years ago
In Exercises 5-7, find all the exact t-values for which the given statement is true,
bearhunter [10]

Answer:  See Below

<u>Step-by-step explanation:</u>

NOTE: You need the Unit Circle to answer these (attached)

5) cos (t) = 1

Where on the Unit Circle does cos = 1?

Answer: at 0π (0°) and all rotations of 2π (360°)

In radians:     t = 0π + 2πn

In degrees:   t = 0° + 360n

******************************************************************************

6)\quad sin (t) = \dfrac{1}{2}

Where on the Unit Circle does   sin = \dfrac{1}{2}

<em>Hint: sin is only positive in Quadrants I and II</em>

\text{Answer: at}\  \dfrac{\pi}{6}\ (30^o)\ \text{and at}\ \dfrac{5\pi}{6}\ (150^o)\ \text{and all rotations of}\ 2\pi \ (360^o)

\text{In radians:}\ t = \dfrac{\pi}{6} + 2\pi n \quad \text{and}\quad \dfrac{5\pi}{6} + 2\pi n

In degrees:    t = 30° + 360n  and  150° + 360n

******************************************************************************

7)\quad tan (t) = -\sqrt3

Where on the Unit Circle does    \dfrac{sin}{cos} = \dfrac{-\sqrt3}{1}\ or\ \dfrac{\sqrt3}{-1}\quad \rightarrow \quad (1,-\sqrt3)\ or\ (-1, \sqrt3)

<em>Hint: sin and cos are only opposite signs in Quadrants II and IV</em>

\text{Answer: at}\  \dfrac{2\pi}{3}\ (120^o)\ \text{and at}\ \dfrac{5\pi}{3}\ (300^o)\ \text{and all rotations of}\ 2\pi \ (360^o)

\text{In radians:}\ t = \dfrac{2\pi}{3} + 2\pi n \quad \text{and}\quad \dfrac{5\pi}{3} + 2\pi n

In degrees:    t = 120° + 360n  and  300° + 360n

4 0
3 years ago
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