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Alisiya [41]
3 years ago
11

How many individual decay steps are in the decay chain of

Chemistry
1 answer:
Lina20 [59]3 years ago
6 0

Answer:

432

Explanation:

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Calculate the maximum solubility of silver carbonate, Ag2CO3 in g/L when in the presence of 0.057 M AgNO3. The solubility produc
Andreyy89

Answer:

Approximately 4.2 \times 10^{-7}\; \rm g \cdot L^{-1}.

Explanation:

Start by finding the concentration of \rm Ag_2CO_3 at equilibrium. The solubility equilibrium for

\rm Ag_2CO_3 \; (s) \rightleftharpoons 2\, Ag^{+}\; (aq) + {CO_3}^{2-}\; (aq).

The ratio between the coefficient of \rm Ag_2CO_3 and that of \rm Ag^{+} is 1:2. For

Let the increase in \rm {CO_3}^{2-} concentration be +x\; \rm mol \cdot L^{-1}. The increase in \rm Ag^{+} concentration would be +2\,x\; \rm mol \cdot L^{-1}. Note, that because of the 0.057\; \rm mol \cdot L^{-1}of \rm AgNO_3, the concentration of

  • The concentration of \rm Ag^{+} would be (0.057 + 2\, x) \; \rm mol\cdot L^{-1}.
  • The concentration of \rm {CO_3}^{2-} would be x\; \rm mol \cdot L^{-1}.

Apply the solubility product expression (again, note that in the equilibrium, the coefficient of \rm Ag^{+} is two) to obtain:

\begin{aligned}&\rm \left[Ag^{+}\right]^2 \cdot \left[{CO_3}^{2-}\right] = K_{\text{sp}} \\ & \implies (0.057 + x)^2\cdot x = 8.1 \times 10^{-12} \end{aligned}.

Note, that the solubility product of \rm Ag_2CO_3, K_{\text{sp}} = 8.1 \times 10^{-12} is considerably small. Therefore, at equilibrium, the concentration of

Apply this approximation to simplify (0.057 + x)^2\cdot x = 8.1 \times 10^{-12}:

0.057^2\, x \approx (0.057 + x)^2 \cdot x = 8.1 \times 10^{-12}.

\begin{aligned} x &\approx \frac{8.1 \times 10^{-12}}{0.057^2}\end{aligned}.

Calculate solubility (in grams per liter solution) from the concentration. The concentration of \rm Ag_2CO_3 is approximately \displaystyle \frac{8.1 \times 10^{-12}}{0.057^2}\; \rm mol\cdot L^{-1}, meaning that there are approximately \displaystyle n = \frac{8.1 \times 10^{-12}}{0.057^2}\; \rm mol of

\begin{aligned}m &= n \cdot M \\ &\approx \displaystyle \frac{8.1 \times 10^{-12}}{0.057^2} \; \rm mol\times 167.91\; g \cdot mol^{-1} \\ &\approx 4.2 \times 10^{-7}\; \rm g \end{aligned}.

As a result, the maximum solubility of \rm Ag_2CO_3 in this solution would be approximately 4.2 \times 10^{-7}\; \rm g \cdot L^{-1}.

8 0
3 years ago
Logs in a fire, and charged batteries are examples of?
vlabodo [156]

Answer:

Logs in a fire is an example of something burning, also changing its state of form. I think thats chemical change; going from wood to ashes. And charged batteries means they haven't been used yet or they were just charged, resulting in physical change.

Explanation:

I just learned this in science.

I hope this helps!

7 0
4 years ago
What is the angle between two of the phosphorus-chlorine bonds in the phosphorus tetrachlory
Korolek [52]

right angle triangle hypotunuse i dnt lnow sorry bro i need pointa

6 0
3 years ago
Temperate deciduous trees lose their leaves in Fall. Explain why trees in temperate rainforest and tropical rainforest don’t los
andrey2020 [161]

Answer:

So trees in temperate don't lose their leaves because the weather events aren't harsh enough.

Trees in tropical rainforest don't lose their leaves because they are a different type of tree known as evergreens that are green all year round.

Explanation:

Ok so first we'll define some things

Deciduous Trees=  Trees that lose all of their leaves for part of the year.

Trees shed their leaves trees to try and survive harsh weather events.

Temperate deciduous trees lose their leaves in fall to better survive the winter conditions of extreme cold and reduced daylight.

Temperate rainforests = An area that doesn't experience extremely cold or extremely hot temperatures or what we would call harsh weather events.

Broad-leaved trees in tropical rainforests are known evergreen, they are known as this as they are green all year round.

6 0
3 years ago
Which is the heaviest element produced in large stars by nuclear fusion near the end of their life cycle?
Rama09 [41]

Iron is the heaviest element produced in large stars by nuclear fusion near the end of their life cycle .

<h3>What do you mean by the nuclear fusion ?</h3>

Nuclear fusion is the process by which two light atomic nuclei combine to form a single heavier one while releasing massive amounts of energy.

The main advantage of nuclear fusion is it is safe source for the generation of electricity.

Characteristics of nuclear fusion -:

  • The main characteristic of nuclear fusion is that it involves formation of a singular particle from two or more atoms.

  • Unlike nuclear fission, nuclear fusion is common in nature- just hard to recreate.

  • Nuclear fusion typically produces few radioactive particles .

  • Fusion works by applying a great deal of pressure to overcome .

Hence ,Iron is the heaviest element produced in large stars by nuclear fusion near the end of their life cycle .

Learn more about nuclear fusion ,here:

brainly.com/question/12701636

#SPJ2

6 0
1 year ago
Read 2 more answers
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