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zheka24 [161]
3 years ago
6

Temperate deciduous trees lose their leaves in Fall. Explain why trees in temperate rainforest and tropical rainforest don’t los

e their leaves. PLEASE HELP!!!!!!!!!!!!! 20 MORE MINUTES UNTIL I HAVE TO HAND THIS INN
Chemistry
1 answer:
andrey2020 [161]3 years ago
6 0

Answer:

So trees in temperate don't lose their leaves because the weather events aren't harsh enough.

Trees in tropical rainforest don't lose their leaves because they are a different type of tree known as evergreens that are green all year round.

Explanation:

Ok so first we'll define some things

Deciduous Trees=  Trees that lose all of their leaves for part of the year.

Trees shed their leaves trees to try and survive harsh weather events.

Temperate deciduous trees lose their leaves in fall to better survive the winter conditions of extreme cold and reduced daylight.

Temperate rainforests = An area that doesn't experience extremely cold or extremely hot temperatures or what we would call harsh weather events.

Broad-leaved trees in tropical rainforests are known evergreen, they are known as this as they are green all year round.

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To find the number of neutrons in a atom, you subtract the number of_____ from the mass number.
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Which is the correctly balanced chemical equation for the reaction of KOH and H2SO4? Which is the net ionic equation for the rea
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Answer:

See explanation

Explanation:

A balanced chemical reaction equation has the same number of atoms of each element on both sides of the reaction equation.

Hence, for the reaction between KOH and H2SO4, the balanced chemical reaction equation is;

H2SO4(aq) + 2KOH(aq) ---------> K2SO4(aq) + 2H2O(l)

Complete ionic equation;

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6 0
3 years ago
Compare the solubility of silver chromate in each of the following aqueous solutions: Clear All 0.10 M AgCH3COO 0.10 M Na2CrO4 0
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$0.10 \ M \ AgCH_3COO$    -----     Less soluble than in pure water.

$0.10 \ M \ Na_2CrO_4$   ----- Less soluble than in pure water.

$0.10 \ M \ NH_4NO_3$   -----   Similar solubility as in the pure water

$0.10 \ M \ KCH_3COO$   -----   Similar solubility as in the pure water

The silver chromate dissociates to form :

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When 0.1 M of $AgCH_3COO^-$ is added, the equilibrium shifts towards the reverse direction due to the common ion effect of Ag^+, so the solubility of Ag_2CrO_4 decreases.

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