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2 years ago

Which is the heaviest element produced in large stars by nuclear fusion near the end of their life cycle?

Chemistry

2 answers:

Rama09 [41]2 years ago

6 0

Iron is the heaviest element produced in large stars by nuclear fusion near the end of their life cycle .

<h3>What do you mean by the nuclear fusion ?</h3>

Nuclear fusion is the process by which two light atomic nuclei combine to form a single heavier one while releasing massive amounts of energy.

The main advantage of nuclear fusion is it is safe source for the generation of electricity.

Characteristics of nuclear fusion -:

The main characteristic of nuclear fusion is that it involves formation of a singular particle from two or more atoms.

Unlike nuclear fission, nuclear fusion is common in nature- just hard to recreate.

Nuclear fusion typically produces few radioactive particles .

Fusion works by applying a great deal of pressure to overcome .

Hence ,Iron is the heaviest element produced in large stars by nuclear fusion near the end of their life cycle .

Learn more about nuclear fusion ,here:

brainly.com/question/12701636

#SPJ2

Sholpan [36]2 years ago

4 0

Answer:

The lightest elements in the universe — hydrogen, helium, and a little lithium — were born shortly after the Big Bang.

Explanation:

You might be interested in

What is the coefficient and the formula 3Zn(NO3)2 represent ?

Mashutka [201]

The answer is 6 nitrogen atoms.

The given chemical formula is : 3Zn(NO₃)₂

Let's find the number of nitrogen atoms by opening the bracket.

3ZnN₂O₆
Zn₃N₆O₁₈

Hence, there are 6 nitrogen atoms.

4 0

2 years ago

4. What is the specific heat of iron, if it requires 1050 J of heat energy to raise the temperature of

Sholpan [36]

Answer:

0.4589J/g°C

Explanation:

Heat energy = 1050J

Mass of iron = 220.0g

Initial temperature (T1) = 10°C

Final temperature (T2) = 20.4°C

Heat energy = mc∇T

Q = mc∇T

Q = heat energy

M = mass of the substance

C = specific heat capacity of the substance

∇T = change in temperature = T2 - T1

Q = m×c×(T2 - T1)

1050 = 220 × c ×(20.4 - 10)

1050 = 220c × (10.4)

1050 = 2288c

c = 1050 / 2288

C = 0.4589J/g°C

The specific heat capacity of iron is 0.4589J/g°C

4 0

3 years ago

Read 2 more answers

In an experiment, 0.42 mol of co and 0.42 mol of h2 were placed in a 1.00-l reaction vessel. at equilibrium, there were 0.29 mol

Likurg_2 [28]

To determine the Keq, we need the chemical reaction in the system. In this case it would be:

CO + 2H2 = CH3OH

The Keq is the ration of the amount of the product and the reactant. We use the ICE table for this. We do as follows:

CO H2 CH3OH
I .42 .42 0
C -0.13 -2(0.13) 0.13
-----------------------------------------------
E = .29 0.16 0.13

Therefore,

Keq = [CH3OH] / [CO2] [H2]^2 = 0.13 / 0.29 (0.16^2)
Keq = 17.51

4 0

4 years ago

A dolphin travels a distance 20 miles up the coastline in 153 minutes.If 1 mile is equal to 1609 meters,then what is the dolphin

Afina-wow [57]

Answer:

The dolphins average speed is 3.51 $\frac{meters}{seconds}$

Explanation:

First of all, the following rules of three should be applied:

If 1 mile is equal to 1609 meters, 20 miles are equal to how many meters?

$distance=\frac{20 miles*1609 meters}{1 mile}$

distance=32,180 meters

If 1 minute is equal to 60 seconds, 153 minutes is equal to how many seconds?

$time=\frac{153 minutes*60 seconds}{1 minute}$

time= 9,180 seconds

Speed is a physical quantity that expresses the relationship between the space traveled by an object and the time used for it. That is, speed implies the change of position of an object in space within a certain amount of time and is calculated as:

$speed=\frac{distance}{time}$

So in this case the velocity is calculated as:

$speed=\frac{32,180 meters}{9,180 seconds}$

Solving, you get:

Speed= 3.51 $\frac{meters}{seconds}$

The dolphins average speed is 3.51 $\frac{meters}{seconds}$

4 0

3 years ago

A student must use 220 mL of hot water in a lab procedure. Calculate the amount of heat required to raise the temperature of 220

Inessa [10]

Answer:

64,433.6 Joules

Explanation:

We are given;

Volume of water as 220 mL
Initial temperature as 30°C
Final temperature as 100°C
Specific heat capacity of water as 4.184 J/g°C

We are required to calculate the amount of heat required to raise the temperature.

We know that amount of heat is calculated by;

Q = mcΔT , where m is the mass, c is the specific heat, ΔT is the change in temperature.

Density of water is 1 g/mL

Thus, mass of water is 220 g

ΔT = 100°C - 30°C

= 70°C

Therefore;

Amount of heat, Q = 220g × 4.184 J/g°C × 70°C

= 64,433.6 Joules

Thus, the amount of heat required to raise the temperature of water is 64,433.6 Joules

7 0

3 years ago