Rachael is wearing roller skates and is
2 answers:
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(a)
The velocity of the meteorite just before hitting the ground is:
The loss of energy of the meteorite corresponds to the kinetic energy the meteorite had just before hitting the ground, so:
(b) 1 megaton of tnt is equal to
To find to how many megatons the meteorite energy loss
corresponds, we can set the following proportion
And so we find
So, 0.162 megatons.
(c) 1 Hiroshima bomb is equivalent to 13 kilotons (13 kT). The impact of the meteorite had an energy of
. So, to find to how many hiroshima bombs it corresponds, we can set the following proportion:
And so we find
So, the energy released by the impact of the meteorite corresponds to the energy of 12.46 hiroshima bombs.
The velocity of the meteorite just before hitting the ground is:
The loss of energy of the meteorite corresponds to the kinetic energy the meteorite had just before hitting the ground, so:
(b) 1 megaton of tnt is equal to
To find to how many megatons the meteorite energy loss
corresponds, we can set the following proportion
And so we find
So, 0.162 megatons.
(c) 1 Hiroshima bomb is equivalent to 13 kilotons (13 kT). The impact of the meteorite had an energy of
And so we find
So, the energy released by the impact of the meteorite corresponds to the energy of 12.46 hiroshima bombs.
Answer:
Explanation:
Mass of object = m
Height above planet = h
Mass of planet = M
Radius of planet = R
As we have to find out velocity, so let's apply the law of conservation of energies on initial( when the object was at height) and final( when object hit the surface points.
Initial energy = Final energy