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Fantom [35]
3 years ago
6

Two radio antennas A and B radiate in phase. Antenna B is a distance of 120 m to the right of antenna A. Consider point Q along

the extension of the line connecting the antennas, a horizontal distance of 40.0 m to the right of antenna B. The frequency, and hence the wavelength, of the emitted waves can be varied. What is the longest wavelength for which there will be destructive interference at point Q?
Physics
1 answer:
LuckyWell [14K]3 years ago
4 0

Answer:

240 m

120 m

Explanation:

d = Path difference = 120 m

For destructive interference

Path difference

d=\dfrac{\lambda}{2}\\\Rightarrow \lambda=2d\\\Rightarrow \lambda=2\times 120\\\Rightarrow \lambda=240\ m

The longest wavelength is 240 m

For constructive interference

d=\lambda\\\Rightarrow 120\ m=\lambda

The longest wavelength is 120 m

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The vehicle's centripetal acceleration is equal to 22.5m/s²

Radius, r = 10 meter

Speed, V = 15 m/s

To ascertain the car's centripetal acceleration

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We obtain the following when we enter the formula's parameters:

A(c) = 152/10

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<h3>What is Centripetal acceleration ?</h3>

When an item moves in a circular route, one of its motion characteristics is centripetal acceleration. Any motion in a circle with an acceleration vector pointing in the direction of the circle's centre is referred to as centripetal acceleration.

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Hence, Centripetal acceleration is

22.5 m/s²

Learn more about Centripetal acceleration here:

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Imagine a player throwing a football. Explain the action of what is happening to the hand and ball, as well as describe the acti
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Answer:

Explanation:

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Answer:

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Charge per volume is given by

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