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ra1l [238]
3 years ago
8

A physics student uses a spring loaded launcher to fire a 58 gram projectile horizontally. The projectile leaves the launcher at

6.0 m/s when the spring is compressed by 2.0 cm.
Physics
1 answer:
timofeeve [1]3 years ago
3 0

Answer:

no answer

Explanation:

the question does not sk what to find

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Two equal-magnitude forces are applied to a door at the doorknob. The first force is applied perpendicular to the door, and the
Leviafan [203]

Answer:

in first case the torque is maximum.

Explanation:

Torque is defined as the product of force and the perpendicular distance.

τ = F x d x Sinθ

In case A: the angle between force vector and the distance vector is 90 so torque is

τ = F x d

In case B: the angle between force vector and the distance is 30°.

τ = F x d x Sin30

τ = 0.5 Fd

So the torque is maximum in first case.

3 0
3 years ago
Starting from zero, an electric current is established in a circuit made of a battery of emf E, a resistor of resistance R and a
igor_vitrenko [27]

Answer:

time constant will decrease and steady state current will decrease on increasing the resistance

Explanation:

As we know that the EMF of cell is E which is used to connected across a resistor and an inductor.

So we will have

E - iR - L\frac{di}{dt} = 0

here we know that

i = \frac{E}{R}(1 - e^{-Rt/L})

now here we have

\tau = \frac{L}{R}

so if we increase the value of resistance of the wire then the time constant will decrease

and hence it will take less time to reach near the steady state value

also the steady state current will be smaller in that case

8 0
3 years ago
Un móvil se encuentra en la posición inicial x0 = 22 m, y se mueve con velocidad 5 m/s. Calcula la posición en la que se encuent
Brilliant_brown [7]

Answer:

La posición en la que se encuentra el móvil en el instante t = 30 s es 172 m.

Explanation:

El movimiento rectilíneo uniforme (MRU) es el movimiento que describe un cuerpo o partícula a través de una línea recta a velocidad constante.

La distancia recorrida,  x , por un móvil que tiene un MRU con un velocidad  v  durante el intervalo de tiempo  t  es:

x= x0 + v*t

donde x0 es la posición inicial.

En este caso:

  • x0= 22 m
  • v= 5 m/s
  • t= 30 s

Reemplazando:

x= 22 m + 5 m/s* 30 s

Resolviendo:

x= 22 m + 150 m

x= 172 m

<u><em>La posición en la que se encuentra el móvil en el instante t = 30 s es 172 m.</em></u>

8 0
3 years ago
Which relations below regarding magnetic field and electric field lines are true? 1. Magnetic field lines never begin nor end bu
Vlad1618 [11]

Answer:

Options 1 and 5 are correct

Explanation:

Magnetic field lines can never cross, the field is unique at any point in space. Magnetic field lines are continuous, forming closed loops without beginning or end. They go from the north pole to the south pole.

Magnetic field lines form closed loops but do not intersect.

Electric field lines originate at the positive charges and terminate at the negative charges. They move in a straight line and are parallel. Electric field lines neither form closed loops nor intersect.

Since, magnetic field lines form closed loops and move from North to South pole, they come out of north poles outside the magnet and into north poles inside the magnet, they also go into south poles outside the magnet and out of south poles inside the magnet.

3 0
3 years ago
If a car goes down Lake at 30 miles per hour how far will it go in 0.25 hours?
kati45 [8]

Answer:

7.5 miles

Explanation:

0.25 hours=15minutes.

So you do

30 miles=60minutes

x =15minutes

cross multiply

Ans-7.5

7 0
3 years ago
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