Answer:
Explanation:
c i think its really blurry and small
Yes unless it is a green arrow. Then you have the right away.
An irrigation fluid that is used for endoscopic procedures using monopolar electrosurgery is Glycine 1.5% solution.
<h3>What is an irrigation fluid?</h3>
This is a fluid that is used for dilation during the process of endoscopic surgery.
What the fluid does is that it helps to wash away dirt from the operating area after it has dilated the area.
Read more on irrigation fluid here: brainly.com/question/13246758
Answer:
a)
b)
Explanation:
From the question we are told that:
Cast-iron block Dimension:
Length
Width
Feed
Depth
Diameter
Number of cutting teeth
Rotation speed
Generally the equation for Approach is mathematically given by
Therefore
Effective length is given as
a)
Generally the equation for Machine Time is mathematically given by
Where
Therefore
b)
Generally the equation for Material Removal Rate. is mathematically given by
Answer:
Hello your question is poorly written below is the well written question and the diagram attached to your question is attached below as w ell
A solid steel shaft ABCDE turns freely in bearings at points A and E. The shaft is driven by the gear at C, which applies a torque T2 325 lb-ft. Gears at B and D are driven by the shaft and have resisting torques T1 200 lb-ft and T3 125 lb-ft, respectively. Segments BC and CD have lengths LBC 20 in. and LCD 15 in. and the shear modulus G 11,600 ksi. Determine the minimum required diameter (d) of the shaft if the allowable shear stress t a 56 ksi. Also calculate the angle of twist between gears B and D.
answer :
a) d ≈ 12.7 inches
b) ∅bc = 1.62 * 10^-3 rad
∅cd = 7.59 * 10^-4 rad
Explanation:
Given data :
G = 11600 ksi
Ta11 = 6 ksi
<u>a) determine the minimum required diameter </u>
Apply the relation below
Toc / Ip = Ta11 / R = G*∅ / L
∴ Ip = Tbc * R / Ta11
π / 32 * (d)^4 = [ ( 200 * 12 ) * ( d/2 )] / 6
therefore : d = 12.7 inches
<u>b) determine angle of twist between gears B and D </u>
attached below is the detailed solution
) ∅bc = 1.62 * 10^-3 rad
∅cd = 7.59 * 10^-4 rad