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Crazy boy [7]
3 years ago
9

"The office personnel at Garden Glory use a database application to record services and related data changes in this database. F

or a new service, the service-recording application reads a row from the OWNED_PROPERTY table to get the PropertyID. It then creates a new row in GG_SERVICE and updates TotalHoursWorked in EMPLOYEE by adding the HoursWorked value in the new PROPERTY_SERVICE record to TotalHours Worked. This operation is referred to as a Service Update Transaction. In some cases, the employee record does not exist before the service is recorded. In such a case, a new EMPLOYEE row is created, and then the service is recorded. This is called a Service Update for New Employee Transaction."
Engineering
1 answer:
KIM [24]3 years ago
3 0

Answer:

b

Explanation:

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Universal Containers uses the Case object to track service tickets. They have implemented Case teams to allow multiple support r
inna [77]

Answer:

Universal Containers uses the Case object to track service tickets. They have implemented Case teams to allow multiple support representatives to manage the Cases. Which two "Filter by owner" options would the user see while creating a list view on the Case object?

Choose 2 answers

A. My Case Teams

B. Roles

C. Public Groups

D. Queue

Correct answer is option A and D

A) My case teams &

D) Queue

Explanation:

Since a case team was implemented to allow multiple support representatives manage the case, the two filter by owner options the user will see are; my case teams and queue.

Queue entails choosing a specific case queue to look at for your view. Which in this case the user will see because the case isn't handled by one person.

In my case teams, cases are filtered to look at only cases where you’re on the case team.

6 0
3 years ago
True or false: You can create a network with two computers.<br><br><br><br> Answer<br> True
coldgirl [10]
To create a computer network, you must have at least two computers. ... A protocol is a standard set of rules and procedures for the control of communications in a network. TRUE. Two computers using TCP/IP can communicate even if they are based on different hardware and software platforms. So your right :)

Hope this helps :)
7 0
2 years ago
Read 2 more answers
There are six items to be rung up in the cash register. The first item costs $15.00. Each item after that costs an additional $2
Paha777 [63]

Answer:

Explanation:

Below is the python code :

#using a for loop that will print the cost of each item

#first item cost is $15.0

item = [15.0]

tcost = 0.0

#for loop to print cost of each item and calculate total cost

for i in range(6):

tcost += item[i]

print('Cost of item ', (i+1), ' : $', item[i], sep = '')

item.append(item[i] + 2)

#print total cost

print('Total cost: $', tcost, sep = '')

print()

#Sequence formula to calculate the total cost

#total cost = n * ((first + last) / 2)

print('Calculating total cost using sequence formula')

tcost2 = 6 * ((15 + 25) / 2)

print('Total cost: $', tcost2, sep = ''

4 0
3 years ago
When is the compressor able to compress the refrigerant?
Dimas [21]

Answer:

The compressor receives low pressure gas from the evaporator and converts it to high pressure gas. As the gas is compressed, the temperature rises. The hot refrigerant gas then flows to the condenser.

3 0
2 years ago
A shaft consisting of a steel tube of 50-mm outer diameter is to transmit 100 kW of power while rotating at a frequency of 34 Hz
nikitadnepr [17]

Answer:

25 - \sqrt[4]{26.66*10^{-8} }  mm

Explanation:

Given data

steel tube : outer diameter = 50-mm

power transmitted = 100 KW

frequency(f) = 34 Hz

shearing stress ≤ 60 MPa

Determine tube thickness

firstly we calculate the ; power, angular velocity and torque of the tube

power = T(torque) * w (angular velocity)

angular velocity ( w ) = 2\pif = 2 * \pi * 34 = 213.71

Torque (T) = power / angular velocity = 100000 / 213.71 = 467.92 N.m/s

next we calculate the inner diameter  using the relation

  \frac{J}{c_{2}  } = \frac{T}{t_{max} }  = 467.92 / (60 * 10^6) =  7.8 * 10^-6 m^3

also

c2 = (50/2) = 25 mm

\frac{J}{c_{2} } = \frac{\pi }{2c_{2} } ( c^{4} _{2} - c^{4} _{1} ) =  \frac{\pi }{0.050} [ ( 0.025^{4} - c^{4} _{1}  ) ]

therefore; 0.025^4 - c^{4} _{1} = 0.050 / \pi (7.8 *10^-6)

c^{4} _{1} = 39.06 * 10 ^-8 - ( 1.59*10^-2 * 7.8*10^-6)

    39.06 * 10^-8 - 12.402 * 10^-8 =26.66 *10^-8

c_{1} = \sqrt[4]{26.66 * 10^{-8} }  =

THE TUBE THICKNESS

c_{2} - c_{1} = 25 - \sqrt[4]{26.66*10^{-8} }  mm

4 0
3 years ago
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