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pychu [463]
3 years ago
13

If you good at math help please!

Mathematics
2 answers:
olganol [36]3 years ago
6 0

Answer:

3 because your domain should not repeat 2 tims.

olchik [2.2K]3 years ago
5 0

Answer:

3 because your domain should not repeat

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Step-by-step explanation:

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Find the limit, if it exists. (If an answer does not exist, enter DNE.)
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Answer:

\lim\limits_{(x,y)\rightarrow(0,0)}\left(\sqrt{x^2+y^2+49}+7\right)=14

Step-by-step explanation:

to find the limit:

\lim\limits_{(x,y)\rightarrow(0,0)}\left(\dfrac{x^2+y^2}{\sqrt{x^2+y^2+49}-7}\right)

we need to first rationalize our expression.

\dfrac{x^2+y^2}{\sqrt{x^2+y^2+49}-7}\left(\dfrac{\sqrt{x^2+y^2+49}+7}{\sqrt{x^2+y^2+49}+7}\right)

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\dfrac{(x^2+y^2)(\sqrt{x^2+y^2+49}+7)}{(x^2+y^2)}

\sqrt{x^2+y^2+49}+7

Now this is our simplified expression, we can use our limit now.

\lim\limits_{(x,y)\rightarrow(0,0)}\left(\sqrt{x^2+y^2+49}+7\right)\\\sqrt{0^2+0^2+49+7}\\7+7\\14

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3 years ago
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