The order of the first eight batters in the batting order is important. For example, if we exchange Jonathan Schoop with Adam Jones in the lineup, that is a different lineup. So we use the permutations formula to solve this problem.

Permutations formula:

The number of possible permutations of x elements from a set of n elements is given by the following formula:

$P_{(n,x)} = \frac{n!}{(n-x)!}$

First 8 batters

8 players from a set of 16. So

$P_{(16,8)} = \frac{16!}{(16 - 8)!} = 518918400$

Last batter:

Any of the four pitchers.

How many different batting orders may occur?

4*518918400 = 2,075,673,600

2,075,673,600 batting orders may occur.

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4 years ago

Which​ rule(s) for exponents did you​ use? Select all that apply.

Which rule(s) for exponents did you use? Select all that apply.