Answer:
<h2>2 m/s²</h2>
Explanation:
The acceleration of an object given it's mass and the force acting on it can be found by using the formula
f is the force
m is the mass
From the question we have
We have the final answer as
<h3>2 m/s²</h3>
Hope this helps you
→ During the formation of a chemical bond, heat is released.
→ Solution that contains all the solute it can hold at a given temperature is saturated.
→ No. of neutrons present in Bromine are 44
They are located outside of the cell.
Answer:
Explanation:
4 = Given data:
Initial volume = 400 mL
Initial pressure = 450 torr
Initial temperature = 210 K
Final temperature = ?
Final volume = 1500 mL
Final pressure = 800 torr
Formula:
P₁V₁/T₁ = P₂V₂/T₂
P₁ = Initial pressure
V₁ = Initial volume
T₁ = Initial temperature
P₂ = Final pressure
V₂ = Final volume
T₂ = Final temperature
Solution:
P₁V₁/T₁ = P₂V₂/T₂
T₂ = P₂V₂ T₁/ P₁V₁
T₂ = 800 torr × 1500 mL × 210 K / 450 torr × 400 mL
T₂ = 252000,000 K / 180000
T₂ = 1400 K
5 = Given data:
Initial volume of gas = 4.5 L
Initial temperature = 25°C (25 + 273 = 298 k)
Final temperature = 25°C×3= 75°C (75+273 = 348 k)
Final volume = ?
Solution:
V₁/T₁ = V₂/T₂
V₁ = Initial volume
T₁ = Initial temperature
V₂ = Final volume
T₂ = Final temperature
Now we will put the values in formula.
V₁/T₁ = V₂/T₂
V₂ = V₁T₂/T₁
V₂ = 4.5 L × 348 K / 298 k
V₂ = 1566 L.K / 298 K
V₂ = 5.3 L
Extra credit:
Given data:
Initial volume = 356 cm³ or 356 mL
Initial pressure = 105000 pa
Initial temperature = 23 °C
Final temperature = ?
Final volume = 560 dL
Final pressure = 36 psi
Formula:
Final volume = 560×100 = 5600 mL
Initial temperature = 23 °C ( 273 + 23 = 296 K)
Final pressure = 36 × 6895 = 248220 Pa
P₁V₁/T₁ = P₂V₂/T₂
P₁ = Initial pressure
V₁ = Initial volume
T₁ = Initial temperature
P₂ = Final pressure
V₂ = Final volume
T₂ = Final temperature
Solution:
P₁V₁/T₁ = P₂V₂/T₂
T₂ = P₂V₂ T₁/ P₁V₁
T₂ = 248220 Pa × 5600 mL × 296 K /105000 pa × 356 mL
T₂ = 411449472,000 K / 37380000
T₂ = 11007.21 K
MgCl2 = 1Mg + 2Cl = 1(24.3) + 2(35.45) = 95.2g/1mole
7.50moles MgCl2 x 95.2g MgCl2 = 714g MgCl2