Answer:
4
Explanation:
Ionization energy can be defined as the energy required for an atom to lose its valence electron to form an ion. Hence, it deals with how easily an atom would lose its electron and form an ion. As the valence electrons are lossless bound to the outermost shell, they can easily be lost without much problem or better still they can be lost easily. Hence, the energy change here is small and thus we can conclude that the ionization energy here is low.
The electron affinity works quite differently from the ionization energy. It deals with the way in which a neutral atom attracts an electron to form an ion. For an electron with loose valence electrons, the sure fact is that it does not really need these electrons. Hence, there is no need for an high electron affinity on its part. Thus, we conclude that the electron affinity is also low
Answer:
Average atomic mass = 85.557 amu.
Explanation:
Given data:
Percent abundance of Rb-85 = 72.15%
Percent abundance of Rb-87 = 27.85%
Average atomic mass = ?
Solution:
Average atomic mass = (abundance of 1st isotope × its atomic mass) +(abundance of 2nd isotope × its atomic mass) / 100
Average atomic mass = (72.15×85)+(27.85×87) /100
Average atomic mass = 6132.75 + 2422.95 / 100
Average atomic mass = 8555.7 / 100
Average atomic mass = 85.557 amu.
By using eyes we can see shapes, colors, and motion around us.
Answer:
This is an acid-base reaction (neutralization): H 2SO 4 is an acid, Ca(OH) 2 is a base.
...
1 H2SO4 + Ca(OH)2 → H2O + CaSO4
2 H2SO4 + Ca(OH)2 → CaSO4 + HOH
3 H2SO4 + Ca(OH)2 → H2O + CaOH2SO4
4 H2SO4 + Ca(OH)2 → H2O + Ca(HSO4)2
5 H2SO4 + Ca(OH)2 → H2O + (CaOH)2SO4
Explanation:
