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baherus [9]
3 years ago
14

Which statement best describes the compressibility of a gas? A Increasing the temperature of a gas decreases the pressure. B Inc

reasing the temperature of a gas increases the pressure. C Increasing the pressure on a gas decreases the volume. D Increasing the pressure on a gas increases the volume.
Chemistry
2 answers:
k0ka [10]3 years ago
8 0

The answer is C. Compressing the air reduces the volume and increases the pressure. Compressing the air causes the molecules to collide with one another, and with the walls of the container, at a higher frequency. This is becaue the number of molecules are still the same but now forced in a smaller volume of space. This why the pressure increases wiht reduced volume, while keeping the temperatures constant.

Iteru [2.4K]3 years ago
5 0

Answer: option C. Increasing the pressure on a gas decreases the volume.

Explanation:

Compressibility is the property of matter that relates the change (decrease) of volume under pressure (compression).

It is defined as the relative change in volume compared to a change in pressure.

Gases under normal conditions of pressure and temperature are highly compressible, since the molecules are widely separated.

You can see the inverse relation between pressure and volume in a gas by looking at the ideal gas equation:

pV = nRT

Hence, constant n, R and T means pV = constant, so as p increases V decreases, which leads to the conclusion stated by the option C: increasing the pressure on a gas decreases the volume.

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Answer: Temperature = T, unknown

Saturated Solution, NH4Cl concentration = 60g/100g H2O = 0.6g NH4Cl/g H2O

Assume density of H2O = 1 g/ml

m = 0.6g NH4Cl/g H2O / 1 g/ml

m = 0.6g NH4Cl/ml

See the table of saturated solutions and identify the temperature at which the concentration of NH4Cl is 60g/100g H2O.

Explanation:  The line on the graph on reference table G indicates a saturated solution of NH4CL as a concentration of 60. g NH4 Cl/100. g H2O

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I’m guessing you mean moles. So the big M stands for mol/L. That means first you’d want to convert your mL to L. To do this write your 250mL then make parenthesis for the conversion. 1L=1000mL
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.250L is what you get. Now we need to figure out how to cancel the L with what we have left. We know M stands for Moles/L so this means in order to get ride of L we need to multiply our new number times the 1.5
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