1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
baherus [9]
3 years ago
14

Which statement best describes the compressibility of a gas? A Increasing the temperature of a gas decreases the pressure. B Inc

reasing the temperature of a gas increases the pressure. C Increasing the pressure on a gas decreases the volume. D Increasing the pressure on a gas increases the volume.
Chemistry
2 answers:
k0ka [10]3 years ago
8 0

The answer is C. Compressing the air reduces the volume and increases the pressure. Compressing the air causes the molecules to collide with one another, and with the walls of the container, at a higher frequency. This is becaue the number of molecules are still the same but now forced in a smaller volume of space. This why the pressure increases wiht reduced volume, while keeping the temperatures constant.

Iteru [2.4K]3 years ago
5 0

Answer: option C. Increasing the pressure on a gas decreases the volume.

Explanation:

Compressibility is the property of matter that relates the change (decrease) of volume under pressure (compression).

It is defined as the relative change in volume compared to a change in pressure.

Gases under normal conditions of pressure and temperature are highly compressible, since the molecules are widely separated.

You can see the inverse relation between pressure and volume in a gas by looking at the ideal gas equation:

pV = nRT

Hence, constant n, R and T means pV = constant, so as p increases V decreases, which leads to the conclusion stated by the option C: increasing the pressure on a gas decreases the volume.

You might be interested in
CH3CH2OH + 302 → 2C02 + 3H2O
Colt1911 [192]

Answer:

Oxygen Gas

Explanation:

The balanced equation shows us the reactant ratio of the reaction.

This means that for every one mole of CH3CH2OH, we need 3 moles of O2 to react with it. Because we need more O2, (3x as much) than ethanol and we have the same given amount (1 mole of each), the oxygen will be the limiting reagent. (1 mole of oxygen would only require 1/3 moles of ethanol to react).

Hope this helped!

7 0
2 years ago
Lead forms two compounds with oxygen. One contains 2.98g of lead and 0.461g of oxygen. The other contains 9.89g of lead and 0.76
aliina [53]

The given question is incomplete, the complete question is:

Lead forms two compounds with oxygen. One contains 2.98g of lead and 0.461g of oxygen. The other contains 9.89g of lead and 0.763g of oxygen. For a given mass of oxygen, what is the lowest whole-number mass ratio of lead in the two compounds that combines with a given mass of oxygen?

Answer:

The lowest whole-number mass ratio in the two compounds is 1:2.

Explanation:

There is a need to find the mole ratio between lead and oxygen atoms in order to find the whole-number mass ratio of lead in the two compounds. In the first compound, the given mass of lead is 2.98 grams, the molar mass of lead is 207.2 gram per mole.  

The no. of moles can be determined by using the formula,  

moles = mass/molecular mass

moles = 2.98 g/207.2 g/mol

= 0.0144 moles

The mass of oxygen in the compound I is 0.461 grams, the molecular mass of oxygen is 16 gram per mol.  

moles = 0.461 g /16 g/mol

= 0.0288 moles

The ratio between the lead and oxygen in the compound I is 0.0144/0.0288 = 1:2

On the other hand, in the compound II, the mass of lead given is 9.89 grams, therefore, the moles of lead in compound II is,  

moles = 9.89 g / 207.2 g/mol

= 0.0477 moles

The mass of oxygen given in compound II is 0.763 grams, the moles of oxygen present in the compound II is,  

moles = 0.763 g / 16 g

= 0.0477 moles

The ratio between the lead and oxygen in the compound II is, 0.0477 moles lead /0.0477 moles oxygen = 1:1

Hence, of the two compounds, the lowest ratio is found in the compound I, that is, 1:2.  

4 0
3 years ago
Predict whether ΔS° is greater than, less than, or approximately zero for each of the following reactions, and explain your choi
inna [77]

Answer:

Explanation:

Entropy -

In a system, the randomness is measured by the term entropy .

Randomness basically refers as a form of energy that can not be used for any work.

The change in entropy is given by amount heat per change in temperature.

  • When solid is converted to gas entropy increases,

As the molecules in solid state are tightly packed and has more force of attraction between the molecules, but as it is converted to gas, the force of attraction between the molecule decreases and hence entropy increases.

So,

The particles of the substance , if are tightly held by strong force of attraction will decrease the entropy ,

And

If the particles are loosely held , the entropy will increase .  

  • If in a reaction , more number of gaseous atoms are present in the product side , entropy will increase , i.e. Δ°S > 0
  • When liquid is converted to solid entropy decreases,  

As the molecules in liquid state are loosely packed and has less force of attraction between the molecules, but as it is converted to solid, the force of attraction between the molecule increases and hence entropy decreases.

  • If in a reaction , less number of gaseous atoms are present in the product side , entropy will decrease , i.e. Δ°S < 0

From the question ,

( a )  NH₃(g) + 5 O₂(g) → 4 NO(g) + 6 H₂O(g)

Gaseous atoms -

Reactant - 1 + 5 = 6

Product - 4 + 6 = 10 ,

Hence ,

More number of gaseous atoms are present in the product side , So ,

entropy will increase , i.e. Δ°S > 0

( b ) CH₄(g) + 2 O₂(g) → CO₂(g) + 2 H₂O(g)

Gaseous atoms -

Reactant - 1 + 2 = 3

Product - 1 + 2 = 3 ,

Since ,

Both the side the value of gaseous atoms are , hence , Δ°S = 0 .

( c ) CaCO₃(s) → CaO(s) + CO₂(g)

Gaseous atoms -

Reactant = 0

Product - 0 + 1 = 1 ,

Since ,

Hence ,

More number of gaseous atoms are present in the product side , So ,

entropy will increase , i.e. Δ°S > 0

8 0
3 years ago
Describe the capillary action in acetone compared to water
lakkis [162]
Capillary action is defined as the ability of a liquid to go up a narrow space without the help or opposition of external forces. One of the most important factors affecting capillary action is the intermolecular forces within a substance. The higher the IMF, the greater the capillary action. The H-bonding in water gives it greater IMF than acetone, so water has greater capillary action.
6 0
3 years ago
Read 2 more answers
In a chemical equation the arrow (indicating a reaction) points in which direction
Murrr4er [49]
Depending if the reaction is a reversible or an irreversible one, the direction of the arrow will point in one direction or 2 directions from reactants to products.
3 0
3 years ago
Read 2 more answers
Other questions:
  • What is the halogen in period 5?? it has six letters
    7·1 answer
  • What volume would 25.0g of Oxygen occupy at STP
    5·1 answer
  • Copper atoms are oxidised at the positive electrode to Cu2+ ions, as shown in the half equation.
    6·1 answer
  • Calculate the molarity (M) if 3.35g of H3PO4 is dissolved in water to give a total volume of 200mL
    6·1 answer
  • How many mole are there in 7.2 x 1023 formula units of H2S04?​
    11·1 answer
  • B.<br> -C-<br> -C-<br> | | |<br> -C-C-C-C-<br> | | |<br> -C-<br> 1<br> TT<br> -C-
    13·2 answers
  • Hydrogen has three isotopes, which include hydrogen, deuterium, and tritium with
    7·1 answer
  • How many moles are in 454 Liters of a gas?
    11·1 answer
  • 12)
    5·1 answer
  • What substitute for fossil fuel depletion has been heralded as the solution to the nation’s energy problems??
    15·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!