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nadezda [96]
2 years ago
10

400 Kelvin to degrees Celsius​

Physics
2 answers:
sineoko [7]2 years ago
5 0

Answer:

400-273

127° C

I hope it's helps you

marissa [1.9K]2 years ago
5 0

Answer:

126.85

Explanation:

hope it helps you!!

brainliest pls

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A body weighing 108N moves with speed of 5m/s in a horizontal
poizon [28]

Answer:

i) 5 m/s^{2}  ii) 54 N  iii) 54 N

Explanation:

i) a = \frac{v^{2}}{r} ⇒ a = 5² ÷ 5 = 5 m/s^{2}

ii) m = \frac{W}{g} ⇒ m = 108 ÷ 10 = 10.8 kg , F = ma ⇒ F = 10.8 × 5 = 54 N

iii) F1 = F2 = 54 N

4 0
3 years ago
A mechanic pushes a 3540 kg car from rest to a speed of v, doing 4864 J of work in the process. Find the speed v. Neglect fricti
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Answer:

1.66 m/s

Explanation:

Work or kinetic energy = \frac{1}{2} mv^{2}

4864=\frac{1}{2} (3540)v^{2}

v = 1.66 m/s

6 0
3 years ago
Consider two celestial objects with masses m1 and m2 with a separation distance between their centers r. If the first mass m1 we
Scilla [17]

The new magnitude of the force of attraction will be 6 times the original force of attraction

<h3>How to determine the initial force </h3>
  • Mass 1 = m₁
  • Mass 2 = m₂
  • Gravitational constant = G
  • Distance apart = r
  • Initial force (F₁) = ?

F = Gm₁m₂ / r²

F₁ = Gm₁m₂ / r²

<h3>How to determine the new force </h3>
  • Mass 1 = 2m₁
  • Mass 2 = 3m₂
  • Gravitational constant = G
  • Distance apart (r) = r
  • New force (F₂) =?

F = Gm₁m₂ / r²

F₂ = G × 2m₁ × 3m₂ / r²

F₂ = 6Gm₁m₂ / r²

But

F₁ = Gm₁m₂ / r²

Therefore

F₂ = 6Gm₁m₂ / r²

F₂ = 6F₁

Thus, the new magnitude of the force of attraction will be 6 times the original force of attraction

Learn more about gravitational force:

brainly.com/question/21500344

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6 0
2 years ago
A material that can easily flow is called a
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A material that can easily flow is called a...

A. Fluid.
3 0
3 years ago
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It is very efficient to drive a large truck to and from school. Please select the best answer from the choices provided T F I th
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It's 100% false, it wastes a ton (sorry for the bad pun!) of gas.

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3 years ago
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