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9966 [12]
2 years ago
12

#8 physics help plssss

Physics
1 answer:
Goshia [24]2 years ago
3 0
For efficiency the top one is 50% and the bottom one is 72%
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(c) What would the angle of reflection be if the incident ray
kvasek [131]

Answer:

So, if a wave hits a mirror at an angle of 36°, it will be reflected at the same angle (36°). ... An incident ray of light hits a plane mirror at an angle and is reflected back off it. The angle of reflection is equal to the angle of incidence. Both angles are measured from the normal.

Explanation:

3 0
2 years ago
Say I have a series circuit with 20v and four 65 ohm resistors, what is the current in each resistor?
Komok [63]
Data:

E = 20 V
R_{1} = 65\Omega
R_{2} = 65\Omega
R_{3} = 65\Omega
R_{4} = 65\Omega

<span>Now that we have all the values ​​we need properly identified, simply calculate the equivalent total resistance of the circuit and the intensity of the total electric current using the Ohm's Law:

</span>R_{T} =  R_{1} + R_{2} + R_{3} + R_{4}
R_{T} = 65 + 65 + 65+ 65
R_{T} = 260\Omega

<span>Like this:
</span>
I_{T} =  \frac{E}{ R_{T} }

I_{T} = \frac{20}{ 260 }
I_{T} = 0,076923076...

\boxed{\boxed{I_{T} \approx 0,07A}} 
Answer:
<span>The intensity of the total electric current 
</span>\boxed{\boxed{I_{T} \approx 0,07A}} 

P.S:. Since the association is in series, the current of 0.07A is the same for all resistors.
4 0
3 years ago
The force of attraction between a -130.0 C and +180.0 C charge is 8.00 N. What is the separation between these two charges in me
kondaur [170]

Answer with Explanation:

The force of attraction between 2 charges of magnitudeq_1,q_2 separated by a distance 'r' is given by

F=\frac{1}{4\pi \epsilon _o}\frac{q_1\times q_2}{r^2}=k\frac{q_1\times q_2}{r^2}

where

\epsilon _o is a constant known as permitivity of free space

k=9\times 10^{9}Nm^2/C^2

Applying the given values in the above relation we get

8=9\times 10^{9}\times \frac{130\times 180}{r^{2}}\\\\r^{2}=\frac{9\times 10^{9}\times 130\times 180}{8}\\\\r^{2}=26325\times 10^{9}\\\\\therefore r=\sqrt{26325\times 10^{9}}=5.131\times 10^{6}meters

5 0
3 years ago
Monochromatic light falls on two very narrow slits 0.046 mm apart. Successive fringes on a screen 6.20 m away are 8.9 cm apart n
Elanso [62]

Answer:

λ = 6.602 x 10^(-7) m

Explanation:

In a double-slit interference experiment, the distance y of the maximum of order m from the center of the observed interference pattern on the screen is given as ;

y = mλD/d

Where;

D is the distance of the screen from the slits = 6.2 m

d is the distance between the two slits = 0.046 mm = 0.046 x 10^(-3) m

The fringes on the screen are 8.9 cm = 0.089 m apart from each other, this means that the first maximum (m=1) is located at y = 0.089 m from the center of the pattern.

Therefore, from the previous formula we can find the wavelength of the light:

y = mλD/d

So, λ = dy/mD

Thus,

λ = (0.046 x 10^(-3) x 0.089)/(1 x 6.2)

λ = 6.602 x 10^(-7) m

8 0
3 years ago
I need help with nine and 10 I will really appreciate it
horsena [70]

Answer:

9] V = D ÷ T

Take any distance value from the graph and its relevant time.

V = 4 ÷ 2

V = 2 m/s

[You will notice that any distance values with its time will give you 2 m/s as its speed. This means that speed is constant throughout.]

10] Take the distance value and its time for the highest peak of B.

V = 20 ÷ 2

V = 10 m/s

7 0
2 years ago
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