Ask question

Ask question

All categories

3 years ago

13

Which of the following can influence one???s ability to detect stimuli and increase one???s responsiveness to stimuli in dangero

us situations?
A.
stimuli criteria
B.
response criteria
C.
difference threshold
D.
detection threshold

Answer: B response criteria

2 answers:

givi [52]3 years ago

7 0

Answer:

B

Explanation:

Edge 2020

kozerog [31]3 years ago

5 0

The answer is B. Response Criteria
I hope this helps!!

You might be interested in

A makes an angel of 30.0 above the positive x-axis, and B makes an angel of 45.0 below the negative x-axis. A=3.00 units and B=2

erik [133]

I think this is vectors. Sketch the two vectors A and B on the x axis and then find their magnitudes using cosine... i would like to know if i am correct.

5 0

3 years ago

The acceleration of an object would increase if there was an increase in the

xxMikexx [17]

As per Newton's II law we know that

$F_{net} = ma$

here we know that

$F_{net} = F_{ap} - F_f$

so here we will have

$a = \frac{F_{ap} - F_f}{m}$

so here if we need to increase the acceleration we need to increase the applied force while on increasing the mass or on increasing the friction force the acceleration will decrease.

So here correct answer will be

<em>A) force on the object.</em>

4 0

3 years ago

What is the strength of an electric field that will put a force of<br> 1.28 x 10-15 N on a proton?

PilotLPTM [1.2K]

Answer: E = 7,490.6 N/C

Explanation:

If we have a field E, and a particle with a charge q, the force that the particle experiences is:

F = E*q

In this case, we know that the force is:

F = 1.2*10^(-15) N

And we know that the particle is a proton, where the charge of a proton is:

q = 1.602*10^(-19) C

Then we can replace these two values in the equation to get:

1.2*10^(-15) N = E*1.602*10^(-19) C

We just need to isolate E.

(1.2*10^(-15) N)/(1.602*10^(-19) C) = E

7,490.6 N/C = E

That is the strength of the electric field.

8 0

3 years ago

The amount of heat needed

Masteriza [31]

J=joules, c=specific heat, q= energy, and the Tf and Ti are the final and initial temperatures cause I couldn't find a delta sign.

$Q=mc(T_{f}-T_{I}) \\ 33000j=2kg*c*80 \\\frac{33000j}{2kg*80} =c \\ c=206.25jkg^{-1}$

4 0

3 years ago

A bowling ball has a mass of 5 kg. A student rolls the bowling ball one time at 1 m/s and a second time and 2 m/s. Compare the m

sasho [114]

The answer is 5kg m/s with the second momentum being 10 kg m/s. i took the test and it was right. hope this helps yalls

5 0

3 years ago