Two runners start simultaneously from the same point on a circular 200-m track and run in the same direction. One runs at a cons
1 answer:
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<span>when it returns to its original level after encountering air resistance, its kinetic energy is decreased.
In fact, part of the energy has been dissipated due to the air resistance.
The mechanical energy of the ball as it starts the motion is:
</span>
<span>where K is the kinetic energy, and where there is no potential energy since we use the initial height of the ball as reference level.
If there is no air resistance, this total energy is conserved, therefore when the ball returns to its original height, the kinetic energy will still be 100 J. However, because of the presence of the air resistance, the total mechanical energy is not conserved, and part of the total energy of the ball has been dissipated through the air. Therefore, when the ball returns to its original level, the kinetic energy will be less than 100 J.</span>
In fact, part of the energy has been dissipated due to the air resistance.
The mechanical energy of the ball as it starts the motion is:
</span>
<span>where K is the kinetic energy, and where there is no potential energy since we use the initial height of the ball as reference level.
If there is no air resistance, this total energy is conserved, therefore when the ball returns to its original height, the kinetic energy will still be 100 J. However, because of the presence of the air resistance, the total mechanical energy is not conserved, and part of the total energy of the ball has been dissipated through the air. Therefore, when the ball returns to its original level, the kinetic energy will be less than 100 J.</span>
Answer:
The velocity is
Henrietta is at distance from the under the window
Explanation:
From the question we are told that
The speed of Henrietta is
The height of the window from the ground is
Generally the time taken for the lunch to reach the ground assuming it fell directly under the window is
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Generally the time taken for the lunch to reach Henrietta is mathematically represented as
Here is the time duration that elapsed after Henrietta has passed below the window the value is given as 4 s
Now
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Generally the distance covered by Henrietta before catching her lunch is
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Generally the speed with which Bruce threw her lunch is mathematically represented as