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posledela
4 years ago
14

the consumer price index compares the cost of goods and services over various years, where 1967 is used as t=0. The same goods t

hat cost $100 in 1967 cost $184.50 in 1977. Find an exponential function to model this data. Estimate what those goods would cost in 2005
Mathematics
1 answer:
Lisa [10]4 years ago
6 0

Answer:

  • f(t) = 100·1.845^(t/10)
  • $1025.15

Step-by-step explanation:

(a) The given numbers can be put directly into the form ...

... f(t) = (initial value) · (ratio)^(t/(time to achieve that ratio))

Here, we have an intial value of $100, and a ratio of $184.50/$100 = 1.845. The time to achieve that multiplication is 10 years (1967 to 1977). So, the equation can be written ...

... f(t) = 100·1.845^(t/10)

(b) You want to find f(38).

... f(38) = 100·1.845^(38/10) = 100·1.845^3.8 ≈ 1025.15 . . . dollars

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a) P(X\geq 1) = 1-P(X

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And replacing we got:

P(X \geq 5) = 1-[0.01+0.02+0.03+0.12+0.11]=1-0.29=0.71

Step-by-step explanation:

For this case we can solve this problem creating the following table

Number of particles      Frequency         Rel. Frequency

             0                            1                       1/100 =0.01

             1                             2                      2/100 =0.02

             2                            3                       3/100=0.03

             3                            12                     12/100=0.12    

             4                            11                       11/100=0.11

             5                            15                      15/100=0.15

             6                            18                      18/100=0.18

             7                            10                       10/100=0.1

             8                            12                       12/100=0.12

             9                            4                         4/100=0.04

             10                           5                         5/100=0.05

             11                            3                         3/100=0.03

             12                           1                          1/100=0.01

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We assume on this case the the relative frequency represent the probability.

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P(X \geq 5) = 1-[0.01+0.02+0.03+0.12+0.11]=1-0.29=0.71

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