Answer:
The final volume will be 3.39 liters
Explanation:
P1V1/T1 = P2V2/T2
P1 = 3 atm
T1 = 19( degrees celsius) + 273 = 292 K
V2 = TO BE DETERMINED
P2 =1 atm
T2 = 22( degrees celsius) + 273 = 295 k
P1V1/T1 = P2V2/T2
V2 = P1V1T2/P2T1 = (3)(1.12)(295)/(1)292) = 3.39 Liters
Answer:
creo que es cinemática, eso creo
Answer : 0.8663 Kg of chalcopyrite must be mined to obtained 300 g of pure Cu.
Solution : Given,
Mass of Cu = 300 g
Molar mass of Cu = 63.546 g/mole
Molar mass of
= 183.511 g/mole
- First we have to calculate the moles of Cu.

The moles of Cu = 4.7209 moles
From the given chemical formula,
we conclude that the each mole of compound contain one mole of Cu.
So, The moles of Cu = Moles of
= 4.4209 moles
- Now we have to calculate the mass of
.
Mass of
= Moles of
× Molar mass of
= 4.4209 moles × 183.511 g/mole = 866.337 g
Mass of
= 866.337 g = 0.8663 Kg (1 Kg = 1000 g)
Therefore, 0.8663 Kg of chalcopyrite must be mined to obtained 300 g of pure Cu.
Answer : The dipole-dipole interaction.
Explanation : The kind of bond that is created by a weak electrical attraction between two polar molecules is dipole-dipole interaction.
The type of force which occurs between the positive end of one molecule and the negative end of another molecule: is dipole-dipole interaction.
For better understanding, please refer the attachment.
Answer:
FALSE.
Explanation:
The right answer is false. There are three different groups of phylum for worms.
Hope this helped!