Answer: See below
Explanation:
n of CO2 = 0.364mmol
Mass of C = 0.364*12 = 4.368 mg
n of H2O = 184.37 = 0.243 mol
The compound has 2*0.243mmol of H
Mass of H = 0.486 mg
Mass of O = 10.68 − (4.368+0.486) = 5.826mg
Moles of O = 0.364
<u>C:H:O Ratios</u>
0.364 : 0.486 : 0.364
= 1 : 1.34 : 1
= 3 : 4 : 3
<u>So the empirical formula is C3H4O3,</u>
Empirical formula mass
= 88= 2 × Molar mass
<u>And the molecular formula is C6H8O6</u>
<em>What volume do 5 moles of a gas occupy at 28 ° C and 3 atm of pressure?</em>
<em />
<h3>Further explanation</h3>
In general, the gas equation can be written

where
P = pressure, atm
V = volume, liter
n = number of moles
R = gas constant = 0.08206 L.atm / mol K
T = temperature, Kelvin
n= 5 moles
T=28 +273=301 K
P=3 atm
The volume of the gas :
