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galben [10]
3 years ago
13

Plz answer this question.....I know the answer for this question but I want to know the explanation plz plz plz I want to know t

he reason for the answer...plz explain properly.....and I also wanted to ask how can we know if a compound is double,triple,single bonded?????
And also how to find the alkene and alkane of a compund if the alkyne is given ...plz answer I need your help .... urgent....I will mark the answer as brainliest..

Chemistry
1 answer:
vlabodo [156]3 years ago
8 0

The compound C_{3}H_{4} will have a triple bond.

Explanation:

A compound which consists of carbon and hydrogen atoms is known as a hydrocarbon.

Alkanes, alkenes and alkynes are all hydrocarbons.

  • General chemical formula of an alkane is C_{n}H_{2n+2}. In an alkane molecule, all the atoms will be bonded through single bonds.

For example, C_{3}H_{8} is propane.

  • General chemical formula of an alkene is C_{n}H_{2n}. An alkene molecule will have atleast one double bond between two carbon atoms.

For example, C_{2}H_{4} is ethene.

  • General chemical formula of an alkyne is C_{n}H_{2n-2}. An alkyne will have atleast one triple bond between two carbon atoms.

For example, C_{3}H_{4} is propyne.

Thus, we can conclude that out of the given options C_{3}H_{4} will have a triple bond.

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3 years ago
If 5.4 moles of Fe react with 4.7 moles of O2, what is the maximum amount of Fe2O3 (in moles) that can be produced? What is the
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Answer:

2.7 moles of Fe₂O₃ is the maximum amount that can be produced. Iron is the limiting reactant.

Explanation:

The balanced reaction is:

4 Fe + 3 O₂ → 2 Fe₂O₃

By reaction stoichiometry (that is, the relationship between the amount of reagents and products in a chemical reaction), the following amounts of each compound participate in the reaction:

  • Fe: 4 moles
  • O₂: 3 moles
  • Fe₂O3: 2 moles

The limiting reagent is one that is consumed first in its entirety, determining the amount of product in the reaction. When the limiting reagent is finished, the chemical reaction will stop.

You can use a simple rule of three as follows: if by stoichiometry 4 moles of Fe reacts with 3 moles of O₂, how much moles of Fe will be needed if 4.7 moles of O₂ react?

moles of Fe =\frac{4. moles of Fe*4.7 moles of O_{2}}{3 moles of O_{2} }

moles of O₂= 6.27

But 6.27 moles of Fe are not available, 5.4 moles are available. Since you have less moles than you need to react with 4.7 moles of O₂, iron Fe will be the limiting reagent.

So you can use a simple rule of three as follows: if by stoichiometry 4 moles of Fe produce 2 moles of Fe₂O₃, how many moles of Fe₂O₃ will be produced if 5.4 moles of Fe react?

moles of Fe_{2}O_{3}=\frac{5.4 moles of Fe*2 moles of Fe_{2} O_{3} }{4 moles of Fe}

moles of Fe₂O₃= 2.7 moles

Then:

<u><em>2.7 moles of Fe₂O₃ is the maximum amount that can be produced. Iron is the limiting reactant.</em></u>

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