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galben [10]
3 years ago
13

Plz answer this question.....I know the answer for this question but I want to know the explanation plz plz plz I want to know t

he reason for the answer...plz explain properly.....and I also wanted to ask how can we know if a compound is double,triple,single bonded?????
And also how to find the alkene and alkane of a compund if the alkyne is given ...plz answer I need your help .... urgent....I will mark the answer as brainliest..

Chemistry
1 answer:
vlabodo [156]3 years ago
8 0

The compound C_{3}H_{4} will have a triple bond.

Explanation:

A compound which consists of carbon and hydrogen atoms is known as a hydrocarbon.

Alkanes, alkenes and alkynes are all hydrocarbons.

  • General chemical formula of an alkane is C_{n}H_{2n+2}. In an alkane molecule, all the atoms will be bonded through single bonds.

For example, C_{3}H_{8} is propane.

  • General chemical formula of an alkene is C_{n}H_{2n}. An alkene molecule will have atleast one double bond between two carbon atoms.

For example, C_{2}H_{4} is ethene.

  • General chemical formula of an alkyne is C_{n}H_{2n-2}. An alkyne will have atleast one triple bond between two carbon atoms.

For example, C_{3}H_{4} is propyne.

Thus, we can conclude that out of the given options C_{3}H_{4} will have a triple bond.

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RoseWind [281]

It is a radio wave

Explanation:

The energy of an electromagnetic waves is related to its frequency by the equation:

E=hf

where

h is the Planck constant

f is the frequency of the wave

We notice that the energy of an electromagnetic wave is proportional to its frequency. This means that waves with higher frequencies, such as gamma rays, x-rays, are more energetic, while waves with lower frequencies, such as microwave and radio waves, are the less energetic.

In this case, we want to find the frequency of a wave with energy

E = 0.000001 eV

Converting into Joules,

E=1\cdot 10^{-6} eV \cdot 1.6\cdot 10^{-19} J/eV=1.6\cdot 10^{-25} J

Solving for the frequency,

f=\frac{E}{h}=\frac{1.6\cdot 10^{-25}}{6.63\cdot 10^{-34}}=2.4\cdot 10^8 Hz = 240 MHz

Which falls in the range of frequency of radio waves.

Learn more about electromagnetic waves:

brainly.com/question/9184100

brainly.com/question/12450147

#LearnwithBrainly

4 0
3 years ago
Hey can u answer this pls
Dmitry_Shevchenko [17]
The answer to your question is DNA!!!!! :)
5 0
3 years ago
Read 2 more answers
How many grams of sodium hydroxide (NaOH) do you need to get rid of 3000 grams of CO2? Don't worry about sig figs for this quest
Slav-nsk [51]

Answer:

It would require 80 g of NaOH .

Explanation:

8 0
3 years ago
Treatment of ethyl acetoacetate with NaOEt (2 equiv) and BrCH2CH2Br forms compound X. This reaction is the first step in the syn
valkas [14]

Answer:

See explanation below

Explanation:

In this reaction we have the ethyl acetoacetate which is reacting with 2 eq of sodium etoxide. The sodium etoxide is a base and it usually behaves as a nucleophyle of many reactions. Therefore, it will atract all the acidics protons in a molecule.

In the case of the ethyl acetoacetate, the protons that are in the methylene group (CH3 - CO - CH2 - COOCH2CH3) are the more acidic protons, therefore the etoxide will substract these protons instead of the protons of the methyl groups. This is because those hydrogens (in the methylene group) are between two carbonile groups, which make them more available and acidic for any reaction. As we have 2 equivalents of etoxide, means that it will substract both of the hydrogen atoms there, and then, reacts with the Br - CH2CH2 - Br and form a product of an aldolic condensation.

The mechanism of this reaction to reach X is shown in the attached picture.

3 0
4 years ago
Which compounds are lewis bases? select all that apply. h―c≡c―h h− nh3 ch3ch2ch3?
Alisiya [41]

The Lewis bases are those which can donate electron pair to an acceptor. These electrons can be a pair of electron that is a lone pair, a negative charge or electrons in a \pi-bond.

  • In H-C\equiv C-H, the presence of \pi-bond make it a Lewis base.
  • In H^{-}, the presence of negative charge makes it a Lewis base.
  • In NH_3, the presence of lone pair on nitrogen makes it a Lewis base.
  • In CH_3CH_2CH_3, there is no lone pair, no \pi-bond, no negative charge so it is not a Lewis base.

Hence, H-C\equiv C-H, H^{-}, and NH_3 are Lewis bases.

8 0
3 years ago
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