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galben [10]
3 years ago
13

Plz answer this question.....I know the answer for this question but I want to know the explanation plz plz plz I want to know t

he reason for the answer...plz explain properly.....and I also wanted to ask how can we know if a compound is double,triple,single bonded?????
And also how to find the alkene and alkane of a compund if the alkyne is given ...plz answer I need your help .... urgent....I will mark the answer as brainliest..

Chemistry
1 answer:
vlabodo [156]3 years ago
8 0

The compound C_{3}H_{4} will have a triple bond.

Explanation:

A compound which consists of carbon and hydrogen atoms is known as a hydrocarbon.

Alkanes, alkenes and alkynes are all hydrocarbons.

  • General chemical formula of an alkane is C_{n}H_{2n+2}. In an alkane molecule, all the atoms will be bonded through single bonds.

For example, C_{3}H_{8} is propane.

  • General chemical formula of an alkene is C_{n}H_{2n}. An alkene molecule will have atleast one double bond between two carbon atoms.

For example, C_{2}H_{4} is ethene.

  • General chemical formula of an alkyne is C_{n}H_{2n-2}. An alkyne will have atleast one triple bond between two carbon atoms.

For example, C_{3}H_{4} is propyne.

Thus, we can conclude that out of the given options C_{3}H_{4} will have a triple bond.

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Answer : 0.8663 Kg of chalcopyrite must be mined to obtained 300 g of pure Cu.

Solution : Given,

Mass of Cu = 300 g

Molar mass of Cu = 63.546 g/mole

Molar mass of CuFeS_2 = 183.511 g/mole

  • First we have to calculate the moles of Cu.

\text{ Moles of Cu}=\frac{\text{ Given mass of Cu}}{\text{ Molar mass of Cu}}= \frac{300g}{63.546g/mole}=4.7209moles

The moles of Cu = 4.7209 moles

From the given chemical formula, CuFeS_2 we conclude that the each mole of compound contain one mole of Cu.

So, The moles of Cu = Moles of CuFeS_2 = 4.4209 moles

  • Now we have to calculate the mass of CuFeS_2.

Mass of CuFeS_2 = Moles of CuFeS_2 × Molar mass of CuFeS_2 = 4.4209 moles × 183.511 g/mole = 866.337 g

Mass of CuFeS_2 = 866.337 g = 0.8663 Kg         (1 Kg = 1000 g)

Therefore, 0.8663 Kg of chalcopyrite must be mined to obtained 300 g of pure Cu.


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