1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
antiseptic1488 [7]
3 years ago
9

What volume of hydrogen will be produced at STP by the reaction of 67.3 g of tin with excess water according to the following re

action?
Chemistry
1 answer:
VikaD [51]3 years ago
5 0

Answer:

Sn + 2H2O ==> Sn(OH)2 + 2H2

67.3 g Sn x 1 mol/119 g x 2 mol H2/mol Sn x 22.4 L/mole = answer in liters

Explanation:

Sn + 2H2O ==> Sn(OH)2 + 2H2

67.3 g Sn x 1 mol/119 g x 2 mol H2/mol Sn x 22.4 L/mole = answer in liters

You might be interested in
Help please hurry pic below
masha68 [24]

Answer:

Hi

Explanation:

5 0
3 years ago
A hydrogen only spectrum
nikklg [1K]

Answer:

yes

Explanation:

6 0
3 years ago
A buffer solution is made that is 0.347 M in H2C2O4 and 0.347 M KHC2O4.
irga5000 [103]

Answer:

1. pH = 1.23.

2. H_2C_2O_4(aq) +OH^-(aq)\rightarrow HC_2O_4^-(aq)+H_2O(l)

Explanation:

Hello!

1. In this case, for the ionization of H2C2O4, we can write:

H_2C_2O_4\rightleftharpoons HC_2O_4^-+H^+

It means, that if it is forming a buffer solution with its conjugate base in the form of KHC2O4, we can compute the pH based on the Henderson-Hasselbach equation:

pH=pKa+log(\frac{[base]}{[acid]} )

Whereas the pKa is:

pKa=-log(Ka)=-log(5.90x10^{-2})=1.23

The concentration of the base is 0.347 M and the concentration of the acid is 0.347 M as well, as seen on the statement; thus, the pH is:

pH=1.23+log(\frac{0.347M}{0.347M} )\\\\pH=1.23+0\\\\pH=1.23

2. Now, since the addition of KOH directly consumes 0.070 moles of acid, we can compute the remaining moles as follows:

n_{acid}=0.347mol/L*1.00L=0.347mol\\\\n_{acid}^{remaining}=0.347mol-0.070mol=0.277mol

It means that the acid remains in excess yet more base is yielded due to the effect of the OH ions provided by the KOH; therefore, the undergone chemical reaction is:

H_2C_2O_4(aq) +OH^-(aq)\rightarrow HC_2O_4^-(aq)+H_2O(l)

Which is also shown in net ionic notation.

Best regards!

4 0
3 years ago
An orgo lab student named Bob wanted to synthesize an isoamyl acetate ester because it smells like bananas and he really likes t
mihalych1998 [28]

Answer:

The answer is "11.07 g".

Explanation:

Isoamyl alcohol is a reagent restriction

Isoamyl alcohol Moles: 

= \frac{7.5}{88.15} \\\\ =0.085

Moles only with the shape of isoamyl acetate are equivalent to numbers.

Isoamyl acetate grams:

= 0.085 \times 130.19\\\\ = 11.07 \ g

3 0
3 years ago
at do oxygen (O) and bromine (Br) have in common? They both tend to gain electrons to gain stability. They both have seven valen
avanturin [10]
Both of them have high electronegativity. Hence they both tend to gain electrons to gain stability.
4 0
3 years ago
Other questions:
  • A gas has a volume of 4.54 L at 1.65 atm and 75.0°C. At what pressure would the volume of the gas be increased to 5.33 L if the
    14·1 answer
  • Calculate the total number of days therapy available within a 300 ml bottle of ranitidine (as hydrochloride) 75 mg/5 ml. oral so
    6·1 answer
  • PLATOFAM HELP!!!!
    15·2 answers
  • How many electrons will a non-metal generally have in its outer shell? 1 - 3 1 - 4 4 - 7 8
    13·2 answers
  • HNO3 + HI = NO + I2 + H2O
    12·1 answer
  • Seawater is typically 3.5% salt and has a density of 1.03 g/mL. How many grams of salt would be needed to prepare enough seawate
    13·1 answer
  • Which of the following ions is in the lowest oxidation state?
    15·2 answers
  • Please explain the difference between reactants and products in a chemical reaction.
    11·1 answer
  • Which statement correctly describes gravity? Group of answer choices an attractive force that acts between all objects without c
    7·2 answers
  • What process must occur to cause sediment to stick together when forming sedimentary rock?
    7·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!