Jamal’s hair is behaving that way because he is in a cold area.
Answer:
M is Li, X is boron, and Q is oxygen. MX is LiB, lithium bromide. QX is BO, boron oxide (not Body Odor).
Explanation: The atomic masses don't match exactly with those listed in the periodic table. Boron, Oxygen, and Lithium come the closest.
Lithium reacts with bromine since it happily donates it's single 2s electron to bromine's 4p orbital to fill bromine's 4s and 4p valence orbitals to go from 7 to 8 valence electrons, it's happy state.
Boron reacts with oxygen to form B2O3, which I'll happily write as O=BOB=O, since my name is Bob. This is more complex, but both elements want to move electrons around in order to reach a more stable electron configuration. Boron has 3 valence electrons and oxygen has 6. So each oxygen needs 2 electrons to fill it's outer shell and boron is happy to lose it's 3 valence electrons to reach an outer shell equiovalent to helium. So 2 borons contribute a total of 6 electrons, and the 3 oxygens have room for a total of 6 electrons to fill their outer shell.
<u>Answer:</u> The molarity of KBr solution is 0.605 M
<u>Explanation:</u>
Molarity is defined as the amount of solute expressed in the number of moles present per liter of solution. The units of molarity are mol/L.
The formula used to calculate molarity:
.....(1)
Given values:
Given mass of KBr = 54.0 g
Molar mass of KBr = 119 g/mol
Volume of the solution = 750 mL
Putting values in equation 1, we get:
Hence, the molarity of KBr solution is 0.605 M
The correct balanced equation of a beta decay undergone by Mercury-203 is as follows:
203 80 Hg → 203 81 + 0 -1 e
<h3>What is beta decay?</h3>
Beta decay in radioactivity refers to the release of a beta particle by a radioactive element.
Beta particle is characterized by the possession of mass number 0 and atomic number -1.
This means that if Mercury-203 undergoes beta decay, the atomic number of the resulting isotope will be +1 as follows:
203 80 Hg → 203 81 Tl + 0 -1 e
Learn more about beta radiation at: brainly.com/question/1580990
