Answer:
High speed internet is typically transmitted around the world;
b. Through fiber optic cables
Explanation:
High speed internet is typically transmitted through fiber optic cables such as the Submarine Cables that makes connection through two cables that connects USA to Europe over the Atlantic Ocean, and the Middle East to Europe Terrestrial Cable Systems (MEETS) which is a cable network of 1,400 km and is being built to have an initial capacity of 200 Gbps
Other example of fiber optic cable assisted internet broadband transmission are the Diverse Route for European and Asian Markets (DREAM) terrestrial cable that connects Germany, Kazakhstan, Russia, and China, TEA NEXT that provides connection between borders on the East and West of Russia and Euro-Russia-Mongolia-China (ERMC) terrestrial cable
Answer:
X=0.194
T=-33.6C
Explanation:
Hello!
To solve this problem use the following steps!
1. We will call the expansion valve inlet 1 and exit 2
2.Through laboratory tests, thermodynamic tables were developed, these allow to know all the thermodynamic properties of a substance (entropy, enthalpy, pressure, specific volume, internal energy etc ..)
through prior knowledge of two other properties such as pressure and temperature.
3. Find the enthalpy of state 1 using pressure and temperature using thermodynamic tables
h1=Enthalpy(Ammonia;T=24C;P=1000kPa)=312.9KJ/kg
4. An expansion valve is a device which does not have heat or work exchange which means that the enthalpy of state one is equal to that of state 2, so using thermodynamic tables uses the pressure of state 2 and enthalpy of state 1 to find quality and temperature
x2=Quality(Ammonia;P=100kPa;h=h1=312.9KJ/kg)
=0.194
T2=Temperature(Ammonia;P=100kPa;h=h1=312.9KJ/kg)=-33.6C
Answer:
12.332 KW
The positive sign indicates work done by the system ( Turbine )
Explanation:
Stagnation pressure( P1 ) = 900 kPa
Stagnation temperature ( T1 ) = 658K
Expanded stagnation pressure ( P2 ) = 100 kPa
Expansion process is Isentropic, also assume steady state condition
mass flow rate ( m ) = 0.04 kg/s
<u>Calculate the Turbine power </u>
Assuming a steady state condition
( p1 / p2 )^(r-1/r) = ( T1 / T2 )
= (900 / 100)^(1.4-1/1.4) = ( 658 / T2 )
= ( 9 )^0.285 = 658 / T2
∴ T2 = 351.22 K
Finally Turbine Power / power developed can be calculated as
Wt = mCp ( T1 - T2 )
= 0.04 * 1.005 ( 658 - 351.22 )
= 12.332 KW
The positive sign indicates work done by the system ( Turbine )
Explanation:
1140 miliohms.
resistance = resistivity×length /area
= 0.0000000171 ohms x 100 meters / 1.5 mm^2