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aliya0001 [1]
3 years ago
15

Estimate properties and pipe diameter Determine the diameter of a steel pipe that is to carry 2000 gal/min of gasoline with a pr

essure drop of 5 psi per 100 ft of horizontal pipe. Pressure drop is a function of flow rate, length, diameter, and roughness. Either iterative methods OR equation solvers are necessary to solve implicit problems. Total head is the sum of the pressure, velocity, and elevation. What is the density of gasoline
Engineering
1 answer:
sp2606 [1]3 years ago
7 0

Answer:

Diameter of pipe is 0.535 ft

Explanation:

see attachment, its works out 1st half

Download pdf
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A tool used to drive and pull out nails​
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2 years ago
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Consider a piston-cylinder device with a piston surface area of 0.1 m^2 initially filled with 0.05 m^3 of saturated water vapor
miv72 [106K]

The friction force f = 10000 N

The heat transfer Q = 1.7936 KJ

<u>Explanation:</u>

Given data:

Surface area of Piston = 1 m^{2}

Volume of saturated water vapor = 100 K Pa

Steam volume = 0.05 m^{3}

Using the table of steam at 100 K pa

Steam density = 0.590 Kg/m^{3}

Specific heat C_{p} = 2.0267 KJ/Kg K

Mass of vapor = S × V

m = 0.590 × 0.05

m = 0.0295 Kg

Solution:

a) The friction force is calculated

Friction force = In the given situation, the force need to stuck the piston.

= pressure inside the cylinder × piston area

= 100 × 10^{3}  × 0.1

f = 10000 N

b)  To calculate heat transfer.

Heat transfer = Heat needs drop temperatures 30°C.

Q=m c_{p} \ DT

Q = 0.0295 × 2.0267 × 10^{3} × 30

Q = 1.7936 KJ

3 0
3 years ago
The roof of a refrigerated truck compartment consists of a layer of foamed urethane insulation (t2 = 21 mm, ki = 0.026 W/m K) be
lakkis [162]

Answer:

Tso = 28.15°C

Explanation:

given data

t2 = 21 mm

ki = 0.026 W/m K

t1 = 9 mm

kp = 180 W/m K

length of the roof is L = 13 m

net solar radiation into the roof = 107 W/m²

temperature of the inner surface Ts,i = -4°C

air temperature is T[infinity] = 29°C

convective heat transfer coefficient h = 47 W/m² K

solution

As when energy on the outer surface at roof of a refrigerated truck that is balance as

Q = \frac{T \infty - T si }{\frac{1}{hA}+\frac{t1}{AKp}+\frac{t2}{AKi}+\frac{t1}{aKp}}       .....................1

Q = \frac{T \infty - Tso}{\frac{1}{hA}}                         .....................2

now we compare both equation 1 and 2 and put here value

\frac{29-(-4)}{\frac{1}{47}+\frac{2\times0.009}{180}+\frac{0.021}{0.026}} = \frac{29-Tso}{\frac{1}{47}}            

solve it and we get

Tso = 28.153113

so Tso = 28.15°C

3 0
3 years ago
2. When performing an alignment, what action should be taken immediately after putting a vehicle on the rack?
mash [69]
D...................
3 0
3 years ago
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