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yKpoI14uk [10]
1 year ago
12

What is the resistance of a resistor if the current flowing through it is 3mA and the voltage across it is 5.3V?

Engineering
1 answer:
Flura [38]1 year ago
6 0

Answer: 1766.667 Ω = 1.767kΩ

Explanation:

V=iR

where V is voltage in Volts (V), i is current in Amps (A), and R is resistance in Ohms(Ω).

3mA = 0.003 A

Rearranging the equation, we get

R=V/i

Now we are solving for resistance. Plug in 0.003 A and 5.3 V.

R = 5.3 / 0.003

= 1766.6667 Ω

= 1.7666667 kΩ

The 6s are repeating so round off to whichever value you need for exactness.

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David wants to determine what his organization should do in the future, and set project targets. Which management function can D
Alinara [238K]

Answer:

Forecasting

Explanation:

Organizational forecasting is estimating of future events for the purpose of effective planning and decision making. This is one of the critical organizational functions as the forecast help managers to anticipate the future and to plan accordingly. Examples are financial forecasting, reporting, and operational metrics tracking, analyze financial data, create financial models use to predict future revenues.

8 0
4 years ago
A charge of 11.748 nC is uniformly distributed along the x-axis from −2 m to 2 m . What is the electric potential (relative to z
svp [43]

Answer:

electric potential  =  22.36 volt

Explanation:

given data

charge Q =  11.748 nC

distance d = 5 - 2 = 3 m

length = 2 + 2 = 4 m

Coulomb constant = 8.98755 × 109 N·m²/C ²

solution

electric potential is express as

electric potential  = \frac{Q}{4\pi \epsilon  _o L} ln(1+\frac{L}{d})   ..............1

electric potential  = \frac{KQ}{L} ln(1+\frac{L}{d})  

put here value

electric potential  = \frac{8.98755\times 10^9\times 11.748\times 10{-9}}{4} ln(1+\frac{4}{3})  

electric potential  =  22.36 volt

6 0
3 years ago
Which step in the engineering design process most likely broke down in the following scenario?
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The Tacoma narrows project required a bridge to be buiilt over the columbia river.

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3 years ago
For a metal casting with a cylindrical riser, what is the best (optimal) aspect ratio (aspect ratio is the ratio of the riser's
DochEvi [55]

Answer:

Optimal aspect ratio = 1

Explanation:

From Chvorinov's Rule,

T = c [\frac{volume}{surface are}]^n

Where

T = solidification time

c = mold constant

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Surface areaA= pi Dh[\frac{2pi D^2}{4}

For the riser to have the longest solidification time:

We have: D = h

V = \frac{pi D^3}{4}

A = pi Dh[\frac{2pi D^2}{4}] = 1.5D^2 pi

Therefore,

\frac{V}{A} = \frac{\frac{pi D^3}{4}}{1.5D^2 pi}

\frac{V}{A} = \frac{D}{6}

To have to longest solidification time, D = h

Therefore the best aspect ratio would be,

\frac{D}{h} = 1

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3 years ago
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