1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
zavuch27 [327]
4 years ago
15

Nitrogen can be liquefied using a Joule-Thomson expansioni process. This is done by rapidlyl and adiabatically expandign cold ni

trogen gas from high pressure to a low pressure. If nitrogen at 135 K and 20 MPa undergoes a Joule-Thomson expansion to 0.4 MPa,
a. Estimate the fraction of vapor and liquid present after the expansion, and the emperature of this mixture using the pressure-enthalpy diagram for nitrogen.

b. Repeat the calculation assuming nitrogen to be an ideal gas with Cp* = 29.3 J/molK
Engineering
1 answer:
solniwko [45]4 years ago
8 0
T is desired to produced liquefied methane as illustrated in problem 1; however, theconditions are now changed so that the gas is initially available at 1 bar and 200 K, and leaving the cooler will be at 100 bar and 200 K. The flash drum is adiabatic, oerates at 1 bar, and each compressor stage canbe assumed to operate reversibly and adiabatically. A three-stage compressor will be used with the first stage compressing the gas fro 1 bar to 5 bar, each stage the gas will be isobarically cooled to 200 K.
You might be interested in
A body is moving with simple harmonic motion. It's velocity is recorded as being 3.5m/s when it is at 150mm from the mid-positio
natima [27]

Answer:

1) A=282.6 mm

2)a_{max}=60.35\ m/s^2

3)T=0.42 sec

4)f= 2.24 Hz

Explanation:

Given that

V=3.5 m/s at x=150 mm     ------------1

V=2.5 m/s at x=225 mm   ------------2

Where x measured  from mid position.

We know that velocity in simple harmonic given as

V=\omega \sqrt{A^2-x^2}

Where A is the amplitude and ω is the natural frequency of simple harmonic motion.

From equation 1 and 2

3.5=\omega \sqrt{A^2-0.15^2}    ------3

2.5=\omega \sqrt{A^2-0.225^2}   --------4

Now by dividing equation 3 by 4

\dfrac{3.5}{2.5}=\dfrac {\sqrt{A^2-0.15^2}}{\sqrt{A^2-0.225^2}}

1.96=\dfrac {{A^2-0.15^2}}{{A^2-0.225^2}}

So    A=0.2826 m

A=282.6 mm

Now by putting the values of A in the equation 3

3.5=\omega \sqrt{A^2-0.15^2}

3.5=\omega \sqrt{0.2826^2-0.15^2}

ω=14.609 rad/s

Frequency

ω= 2πf

14.609= 2 x π x f

f= 2.24 Hz

Maximum acceleration

a_{max}=\omega ^2A

a_{max}=14.61 ^2\times 0.2826\ m/s^2

a_{max}=60.35\ m/s^2

Time period T

T=\dfrac{2\pi}{\omega}

T=\dfrac{2\pi}{14.609}

T=0.42 sec

8 0
4 years ago
What are trouble code charts?
Goshia [24]

Answer:

something that involves cars

Explanation:

6 0
3 years ago
Activity
Sphinxa [80]

Answer:

yo do you still need an

answer

Explanation:

6 0
4 years ago
A full journal bearing has a shaft diameter of 3.000 in with a unilateral tolerance of -0.0004 in. The l/d ratio is unity. The b
sashaice [31]

Answer:

i) 154°F

ii) 0.0114 mm

iii) 0.075 btu/s

iv) 0.080 in^3/s

Explanation:

<u>i)Determine the average film Temperature </u>

( from Viscosity-temperature chart in US customary units for SAE10 )

at Temp =  154°F

absolute viscosity = 4.25 rev

and ΔT = 2 ( 154 - operating temp ) = 28°F

where : operating temp = 140°F as given in question

also from the chart applying Raimondi and Boyd boundary conditions

ΔT = 29°F  hence we can pick 154°F as the average film temperature

<u>ii) Calculate the minimum film thickness</u>

Cmin = Bore diameter - Journal shaft diameter / 2

         = 3.003 - 3 / 2 = 0.0015 in

Given that : h₀ / Cmin = 0.76

there h₀ = 0.0015 * 0.76 = 0.0114 mm

<u>iii)Determine the heat loss rate </u>

Also known as power loss ratio ( H ) = ( 2π*w*f*r*N ) / ( 778 *12 )

( 2π * 0.0132 * 675 * 1.5 * 10 ) / ( 9336 )

Heat loss rate = 0.075 btu/s

<u>iv)Calculate lubricant side-flow rate for minimum clearance assembly </u>

Side flow rate = 0.315 * Total volume flow rate

                       = 0.315 * ( 3.8 * 1.5 * 0.0015 * 10 * 3 )

                      = 0.080 in^3/s.

6 0
3 years ago
Alicia had to get over her fear of heights in order to become comfortable maintaining the generators in wind turbines. professio
kow [346]

Answer:a

Explanation:

5 0
3 years ago
Other questions:
  • Data becomes information when it is__________ in some way and made___________
    5·1 answer
  • Elizabeth has been asked to design a pool umbrella that can withstand wind speeds of up to 30 miles per hour. Now that she under
    12·2 answers
  • What are the desired characteristics or values for the following parameters of an ideal amplifier?o Phase change as a function o
    10·1 answer
  • The occupants of a remote village rely exclusively on a single micro hydro facility for all of their electricity needs. The hydr
    7·1 answer
  • How is the minimum circuit ampacity for an air-conditioning condensing unit calculated?
    7·1 answer
  • Which geometric curved solids are most commonly used by engineers?
    8·2 answers
  • Determine the voltage drop from the top terminal to the bottom terminal, vab, in the right hand branch and, vcd, in the left han
    6·1 answer
  • True or False: Stress can effectively be relieved through physical activity, getting enough rest and sleep, and relaxation techn
    7·2 answers
  • Which is an alloy made up of iron and carbon and has high compressive and tensile strength?
    11·1 answer
  • Why dose bob not let humans touch him one and only Ivan
    8·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!